Question

我想知道每个单独的播放列表中的观看次数，我可以在其中存储阵列中每个观看次数的观看次数，然后在模板中显示它，但在模板中的以下内容中显示该阵列：

[1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] [1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] [1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] [1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] [1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] [1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] [1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] [1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] [1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] [1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] [1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] [1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] [1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] [1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

这里数组被播放列表重复了，我不能在数组的元素之间移动

问题2：我无法确定每人的观看次数


def playlist_view(request,id):
    category = get_object_or_404(Category,pk=id)
    playlists = Playlist.objects.filter(category=category)

    views=list()
    for playlist in playlists:
        views.append(PlaylistView.objects.filter(playlist=playlist).count())
    print(views)

    return render(request, 'playlist.html',{'category': category,'playlists': playlists,'views':views})

                    {% for playlist in playlists %}
                    {{ views }} :: {{ playlist.name }}

                        {% endfor %}

def track_view(request,id_category,id_playlist):
    category = get_object_or_404(Category, pk=id_category)
    playlist= get_object_or_404(Playlist,pk=id_playlist)

    if not PlaylistView.objects.filter(playlist=playlist, session=request.session.session_key):
        x_forwarded_for = request.META.get('HTTP_X_FORWARDED_FOR')
        if x_forwarded_for:
            ip = x_forwarded_for.split(',')[0]
        else:
            ip = request.META.get('REMOTE_ADDR')
        view = PlaylistView(playlist=playlist, ip=ip, created_dt=datetime.now(), session=request.session.session_key)
        view.save()

这是对Array元素的正确访问，但不能同时访问播放列表

      {% for view in views %}
                    {{ view }}
      {% endfor %}

      {% for playlist in playlists %}
              {{ views }} :: {{ playlist.name }}
      {% endfor %}

如何在同一循环中访问两个数组

Answer 1

正如我所看到的，您需要每个播放列表的视图，在这种情况下，您可以使用setattr（）函数将视图计数设置为播放列表对象。但是更好的方法是进行这样的查询

from django.db.models.aggregates import Count

Playlist.objects.filter(category=category).annotate(view_count= Count('related_name'))

注意：相关名称应来自带有播放列表的PlaylistView外键字段。比您可以像这样访问-

for playlist in playlists:
    {{ playlist.view_count }} :: {{ playlist.name }}

对于每个播放列表的播放列表视图，您可以编写如下查询：

playlist = Playlist.objects.filter(category=category).prefetch_related(Prefetch('related_name', PlaylistView.objects.all(), 'my_list'))

然后您可以访问该查询集，例如：

for playlist in playlists:
        {{ playlist.view_count }} :: {{ playlist.name }}
        for view in playlist.my_list:
            {{view}}

Answer 2

感谢您的回复，但是每个类别都有很多播放列表，每个播放列表都有很多PlaylistView。

我已经成功存储了每个播放列表的PlaylistView：

def track_view(request,id_category,id_playlist):
    category = get_object_or_404(Category, pk=id_category)
    playlist= get_object_or_404(Playlist,pk=id_playlist)

    if not PlaylistView.objects.filter(playlist=playlist, session=request.session.session_key):
        x_forwarded_for = request.META.get('HTTP_X_FORWARDED_FOR')
        if x_forwarded_for:
            ip = x_forwarded_for.split(',')[0]
        else:
            ip = request.META.get('REMOTE_ADDR')
        view = PlaylistView(playlist=playlist, ip=ip, created_dt=datetime.now(), session=request.session.session_key)
        view.save()

如何在此处（在另一页上）了解每个播放列表的播放列表视图：

def playlist_view(request,id):
    category=get_object_or_404(Category,pk=id)
    playlists=Playlist.objects.filter(category=category)

    for playlist in playlists:
        PlaylistView.objects.filter(playlist=playlist).annotate(view_count=Count('playlistviews'))

感谢阿吉安！

数组不在模板中访问

2 个答案: