Question

我正在尝试在Laravel中使用日期过滤器。除了start_date和end_date是相同的日期之外，其他一切都正常。然后除了我加1以外，没有其他结果。

    public function userresponseReport(Request $request)
{
    $data['title'] = 'User Response';

    $userresponses = DB::table('user_response as g')
    ->select(
       DB::raw('DATE(g.created_at) as created_date'),
       'g.msisdn', 
       'g.game_code', 
       'g.answer',
       'g.answer_code',
       'g.Amount_charged',
       'g.payment_ref',
       'g.status',
       'g.user_channel'                
  )               
 ->orderByRaw('g.created_at DESC'); 

    $render=[];  
    if(isset($request->start_date) && isset($request->end_date))
    {
        $userresponses=$userresponses->whereBetween('created_at',[$request->start_date,$request->end_date]);

        $render['start_date']=$request->start_date;
        $render['end_date']=$request->end_date;
    }elseif(isset($request->start_date))
    {
        $userresponses=$userresponses->where('created_at',$request->start_date);
        $render['start_date']=$request->start_date;
    }                
    $userresponses= $userresponses->orderBy('created_at','DESC');
    $userresponses= $userresponses->paginate(15);
    $userresponses= $userresponses->appends($render);
    $data['userresponses'] = $userresponses;

return view('report.userresponseReport',$data);        
}

我该如何解决？

Answer 1

您可以将whereDate()与>=和<=运算符一起使用。请注意，whereDate()方法将从datetime表达式中删除日期部分。因此，对于同一日期，查询将返回该日期的所有寄存器created_at。

$date_from = $request->start_date;
$date_to = $request->end_date;
$render=[];
$userresponses = DB::table('user_response as g')
    ->select(
       // ...               
  )               
 ->orderByRaw('g.created_at DESC')
 ->when($date_from, function($query) use ($date_from, $render) {
     $render['start_date'] = $date_from;
     $query->whereDate('created_at', '>=', $date_from);
 })
 ->when($date_to, function($query) use ($date_to, $render) {
     $render['end_date'] = $date_to;
     $query->whereDate('created_at', '<=', $date_to);
 })
 ->orderBy('created_at','DESC')
 ->paginate(15);

如果要比较日期时间，请使用where()。同样，您可以与运营商 <= 和 {{11]解决问题“如果开始日期和结束日期不在同一日期” }} 。

>=

但是很难找到从日期时间// ... ->when($date_from, function($query) use ($date_from, $render) { $render['start_date'] = $date_from; $query->where('created_at', '>=', $date_from); }) ->when($date_to, function($query) use ($date_to, $render) { $render['end_date'] = $date_to; $query->where('created_at', '<=', $date_to); })到同一日期时间的记录，只有在精确的秒内创建了记录的情况下，它才会返回某些内容。

Answer 2

如果开始日期和结束日期相同，您仍要返回结果？

您可以使用class ViewController: UIViewController { let tapGesture : UIGestureRecognizer! func viewDidLoad() { self.tapGesture = UITapGestureRecognizer(target: self, action: #selector(ViewController.move(tap:)))。

orWhere

Laravel-搜索日期之间的问题

2 个答案: