Question

我有2张桌子-1张with forum category name field called "disp_name" and "ID" called "forum_cat" 还有另一个with forum posts id, forum post content and cat_id and more called "forum"

我有模型“ Forum_cats”

    <?php

    namespace App;

    use Illuminate\Database\Eloquent\Model;

    class Forum_cats extends Model
    {

    protected $table = 'forum_cat';

    public $timestamps = false;

    }

和模型“论坛”

<?php

namespace App;

use Illuminate\Database\Eloquent\Model;

class Forum extends Model
{   

protected $table = 'forum';

public $timestamps = false;

}

控制器：

public function index(){


    $forum = Forum::orderBy('timestamp', 'desc')->paginate(20);

//next variable is for different place
    $news = Neww::orderBy('date', 'DESC')->paginate(20);


    return view ('lapas.pamata.index',[
        'news'=>$news,
        'forum'=> $forum,
    ]);
}

刀片：

@foreach($forum as $forums)
          <li>
            <div class="media">
              <div class="media-body"> <a href="#" class="catg_title"> 
              {{$forums->title}}</a> </div>
              <i class="far fa-comment-alt"></i>&nbsp;{{$forums->comments}} 
              Kategorija:{{$forums->cat_id}}
            </div>
          </li>
        @endforeach

因此当前的视图为like this where after "Kategorija" i have only category id

如何从表“ forum_cat”中以名称“ Kategorija”输出字段“ disp_name”。

有人可以说关于我的问题有很多帖子，但是我整天都在努力解决这个问题。我知道它关于hasOne，belongsTo和hasMany，但是我不明白我们在我的代码中如何对它们进行纠正。

Answer 1

因此，我假设（但仍不确定）该论坛属于某个类别。

您的论坛模型应为：

<?php

namespace App;

use Illuminate\Database\Eloquent\Model;

class Forum extends Model {   

    protected $table = 'forum';
    public $timestamps = false;

    public category(){
            return $this->belongsTo('App\Forum_cats', 'cat_id', 'id');
    }
}

您的刀片应该是：

@foreach($forum as $forums)
          <li>
            <div class="media">
              <div class="media-body"> <a href="#" class="catg_title"> 
              {{$forums->title}}</a> </div>
              <i class="far fa-comment-alt"></i>&nbsp;{{$forums->comments}} 
              Kategorija:{{$forums->category->disp_name}}
            </div>
          </li>
@endforeach

这对您有用吗？您还可以考虑增加负载：

https://laravel.com/docs/5.8/eloquent-relationships#constraining-eager-loads

如何显示其他表格中的类别名称而不是类别ID

1 个答案: