Question

我有一个表格，看起来像下面的示例。

const appoint = [{"a":"asas","b":{"au":false,"h":false,"l":true}},{"a":"avd","b":{"au":true,"h":false,"l":true}},{"a":"as","b":{"au":true,"h":false,"l":false}}]
  
const getKeysBy = (predicate, obj) => 
  Object.entries(obj)
  .filter(([, v]) => predicate(v))
  .map(([k]) => k)
  
const result = appoint.flatMap(o => getKeysBy(v => v !== false, o.b))

console.log(result)

对于进一步绘制，我想进行绘制，这取决于海拔高度和dequence_number。

是否有可能获得依赖于两个值的均值：

  Timestamp Scan_ID LOS_ID  ... Radial_Wind_Speed_[m/s] CNR_[dB] Confidence_Index_Status
0      2019-04-04 23:01:00.147      26      4  ...                    0.04   -11.66                       1
1      2019-04-04 23:01:00.147      26      4  ...                   -0.18   -12.89                       1
2      2019-04-04 23:01:00.147      26      4  ...                    0.00   -12.27                       1
3      2019-04-04 23:01:00.147      26      4  ...                    0.12   -10.58                       1
4      2019-04-04 23:01:00.147      26      4  ...                    0.17    -6.32                        1

最佳和谢谢

平均分组依据取决于两列

0 个答案: