如何在SQL时间“ HH：MM”中转换int列？

Question

如何将 int“小时” 和 Int“分钟” 转换为时间，然后获得两个不同时间的百分比？

从我正在使用的 int 列中获取总时间

Format((SUM([THOURS]) * 3600 + SUM([TMINUTES]) * 60 + SUM([TSECONDS])) / 3600,'00')+':'+Format((SUM([THOURS]) * 3600 + SUM([TMINUTES]) * 60 + SUM([TSECONDS])) % 3600/60,'00') as "Total Time"

我从上述查询中得到了完美的时光。

但是现在我希望从我的两个 int“小时” 和 Int“分钟” 列表中获取百分比计算。

我尝试过

DECLARE @MS INT = 235216
select cast(dateadd(ms, @MS, '00:00:00') AS TIME(3))

这不是我的要求。

有人有相同的想法吗？

Answer 1

也许这会有所帮助：

declare @A table 
  ( xHours int, xMinutes int, xSeconds int, 
    yHours int, yMinutes int, ySeconds int  )

insert into @A ( xHours, xMinutes, xSeconds, yHours, yMinutes, ySeconds ) values
( 7, 23, 59, 13, 44, 51 ),
( 0, 00, 12,  1, 07, 00 );

with A as ( select *, 
            3600 * xHours + 60 * xMinutes + xSeconds as xTotal,
            3600 * yHours + 60 * yMinutes + ySeconds as yTotal 
            from @A ),
B as ( select *, 
       cast ( DATEADD(second,xTotal,'00:00:00') as time(0)) as xTime,
       cast ( DATEADD(second,yTotal,'00:00:00') as time(0)) as yTime
 from A ),
C as ( select *, 100*CAST(xTotal as float)/CAST(yTotal as float) as Usage from B )
select xTotal, yTotal, xTime, yTime, Usage from C

结果：

xTotal  yTotal     xTime     yTime  Usage
 26639   49491  07:23:59  13:44:51  53.8259481521893
    12    4020  00:00:12  01:07:00  0.298507462686567

Answer 2

将时间字段转换为分钟，然后对分钟进行数学运算。此示例使用两个变量-您将改用字段名。

Declare
    @Allotted As Time = '08:00'
    , @Taken As Time = '06:00'

    Select Cast(DateDiff(Minute, '00:00', @Taken) As Numeric(17, 2)) / DateDiff(Minute, '00:00', @Allotted) as Percent_Of_Allotted_Time