使用QStackedLayout

Question

我正在尝试使用QStackedLayout创建动态堆叠布局。该程序运行正常。但是，当我动态创建一个新窗口时，我注意到它在转换之前会冻结一段时间。基本上，一个窗口通过QLineEdits要求用户输入，并在按下Submit按钮后，它连接到change_window方法，该方法创建一个新的小部件，并将其与用户输入的详细信息一起添加到主堆栈中，然后进行切换到新创建的布局。下一个窗口（即使用上一个窗口中用户的输入创建X个按钮）。以前，我尝试在主UI控制器上与其他窗口一起创建下一个窗口，但是由于所有布局都是在第一个实例期间创建的，因此调用它不会更新布局。有更好的方法吗？

主界面类

class UI(QMainWindow):
    def __init__(self):

    super().__init__()
    self.setWindowTitle("Main Window")

    # Set dimensions and fix scaling
    width, height = 480, 720
    self.setFixedSize(width, height)

    # Center to the screen
    qr = self.frameGeometry()
    cp = QDesktopWidget().availableGeometry().center()
    qr.moveCenter(cp)
    self.move(qr.topLeft())

    # Create a stack object
    self.stacked_layout = QStackedLayout()

    # Set central widget
    self.central_widget = QWidget(self)
    self.central_widget.setLayout(self.stacked_layout)
    self.setCentralWidget(self.central_widget)

    # Create window widgets
    self.main_window = MainWindow(self)
    self.popup_window = PopupWidget(self)
    self.detail_window = DetailWindow(self)
    # self.input_window = InputWindow(self)

    # Add the main window widget to the stack
    self.stacked_layout.addWidget(self.main_window)
    self.stacked_layout.addWidget(self.popup_window)
    self.stacked_layout.addWidget(self.detail_window)
    # self.stacked_layout.addWidget(self.input_window)

在“详细信息窗口”类中更改窗口方法

class DetailWindow(QWidget):
    def __init__(self, main):
        super().__init__()
        self.parent = main

        # Enable styling and set background
        self.setAttribute(Qt.WA_StyledBackground)
        self.setObjectName("detail")
        self.setStyleSheet('''#detail{background-image:
                        url(resources/images/detail_bg.jpg)}''')
        self.installEventFilter(self)

        # Create the line edits
        self.label_width, self.label_height = (74, 40)
        self.examinee_edit = self.create_line_edit(322, 264, 2)
        self.question_edit = self.create_line_edit(322, 332, 2)
        self.choices_edit = self.create_line_edit(322, 397, 2)

        # Create labels
        self.examinee_label = self.create_labels(84, 270, "Number of Examinees")
        self.question_label = self.create_labels(84, 342, "Number of Questions")
        self.choices_label = self.create_labels(84, 404, "Number of Choices")

        self.prompt1 = self.prompt_label(86, 294)
        self.prompt2 = self.prompt_label(86, 364)
        self.prompt3 = self.prompt_label(86, 427)

        # Create the submit button
        self.create_submit_button()

        # Go to the next line edit if enter/return is pressed
        self.examinee_edit.returnPressed.connect(lambda: self.question_edit.setFocus())
        self.question_edit.returnPressed.connect(lambda: self.choices_edit.setFocus())
        self.choices_edit.returnPressed.connect(lambda: self.submit.setFocus())

    def change_window(self):
        print('Current Window:', self.parent.stacked_layout.currentIndex())
        line_edit_list = (self.examinee_edit, self.question_edit, self.choices_edit)
        label_list = (self.examinee_label, self.question_label, self.choices_label)
        prompt_list = (self.prompt1, self.prompt2, self.prompt3)

        if self.examinee_edit.hasAcceptableInput() and self.question_edit.hasAcceptableInput() and self.choices_edit.hasAcceptableInput():
            next_window = InputWindow(self.parent, self.examinee_edit.text())
            self.parent.stacked_layout.addWidget(next_window)
            self.parent.stacked_layout.setCurrentIndex(3)
        else:
            self._input_prompt(label_list, line_edit_list, prompt_list)