原始问题:
就像这张照片一样,但是有一个完整的三角形。而且我需要能够设置行x1,y1,x2,y2。谢谢!
this image (can't post it because I ain't got enogh reputation)
编辑:
我正在使用“ react-native-svg”:这是我的意思:
<Svg
height="1000"
width="1000"
>
<Line
x1={this.state.circle1.x}
y1={this.state.circle1.y}
x2={this.state.circle2.x}
y2={this.state.circle2.y}
stroke="#1abc9c"
strokeWidth="10"
/>
</Svg>
答案 0 :(得分:0)
好的,所以我知道了。这可能是一个非常糟糕的实现,但确实可行。如果有人可以改善此答案,请执行:
<Svg
height="1000"
width="1000"
>
<G
rotation={(Math.atan2(this.state.point2.y - this.state.point1.y, this.state.point2.x - this.state.point1.x) * 180 / Math.PI)+45}
origin={`${this.state.point1.x}, ${this.state.point1.y}`}
>
<Path d={`M ${this.state.point1.x+8} ${this.state.point1.y+8} L ${this.state.point1.x-10} ${this.state.point1.y+10} L ${this.state.point1.x-8} ${this.state.point1.y-8} z`} fill="#1abc9c" stroke="#1abc9c" />
</G>
<G
rotation={(Math.atan2(this.state.point2.y - this.state.point1.y, this.state.point2.x - this.state.point1.x) * 180 / Math.PI)-135}
origin={`${this.state.point2.x}, ${this.state.point2.y}`}
>
<Path d={`M ${this.state.point2.x+8} ${this.state.point2.y+8} L ${this.state.point2.x-10} ${this.state.point2.y+10} L ${this.state.point2.x-8} ${this.state.point2.y-8} z`} fill="#1abc9c" stroke="#1abc9c" />
</G>
<Line
x1={this.state.point1.x}
y1={this.state.point1.y}
x2={this.state.point2.x}
y2={this.state.point2.y}
stroke="#1abc9c"
strokeWidth="10"
/>
</Svg>