每个“ OR”条件的第一行

时间:2019-06-27 18:33:23

标签: sql sql-server where-clause

我有一个查询:

SELECT ID, Name, EventTime FROM table
    WHERE Name = 'value1' AND EventTime < timeValue1
       OR Name = 'value2' AND EventTime < timeValue2
       OR Name = 'value3' AND EventTime < timeValue3
       ...
ORDER BY EventTime DESC

每个条件Name = ... AND EventTime < ...可以返回多行,但是根据OR子句,我只需要每个ORDER BY条件的第一行。

有什么方法可以实现这一目标或解决方法吗?

5 个答案:

答案 0 :(得分:2)

在我看来您正在搜索row_number()

  select * from (  SELECT ID, Name, EventTime
    , row_number() over(partition by Name order by  EventTime DESC) rn  FROM table
    WHERE Name = 'value1' AND EventTime < timeValue1
       OR Name = 'value2' AND EventTime < timeValue2
       OR Name = 'value3' AND EventTime < timeValue3
       ...
  ) a where a.rn=1

答案 1 :(得分:1)

;
WITH A
AS
(
    SELECT *, ROW_NUMBER()OVER(PARTITION BY [GROUP] ORDER BY 1) as RN
    FROM 
    (
            SELECT ID, Name, EventTime,  
            CASE WHEN Name = 'value1' AND EventTime < timeValue1 THEN '1'
                 WHEN Name = 'value2' AND EventTime < timeValue2 THEN '2'
                 WHEN Name = 'value3' AND EventTime < timeValue3 THEN '3'
                 WHEN Name = 'value3' AND EventTime < timeValue4 THEN '4'
                 --Could be more here
                 END as [Group]
            FROM table
    )
) 
SELECT * FROM A WHERE RN = 1
ORDER BY EventTime DESC

答案 2 :(得分:1)

我想我会这样处理:

SELECT ID, Name, EventTime
FROM (SELECT t.*,
             ROW_NUMBER() OVER (PARTITION BY name ORDER BY t.eventtime DESC) as seqnum
      FROM table t JOIN
           (VALUES ('value1', timevalue1), ('value2', timevalue2), ('value3', timevalue3)
           ) v(name, timevalue)
           ON t.name = v.name and t.eventtime < v.timevalue
     ) t
WHERE seqnum = 1
ORDER BY EventTime DESC;

我更喜欢将派生表用于此类重复值,而不是将其嵌入查询逻辑中。

答案 3 :(得分:0)

您可以尝试:

SELECT Top (1) ID, Name, EventTime FROM table
    WHERE Name = 'value1' AND EventTime < timeValue1
       OR Name = 'value2' AND EventTime < timeValue2
       OR Name = 'value3' AND EventTime < timeValue3
       ...
ORDER BY EventTime DESC

答案 4 :(得分:0)

只要您的所有列名都相同,就可以使用联合。

SELECT top 1 ID, Name, EventTime FROM table
WHERE Name = 'value1' AND EventTime < timeValue1
ORDER BY EventTime DESC
UNION
SELECT top 1 ID, Name, EventTime FROM table
WHERE 
    Name = 'value2' AND EventTime < timeValue2
ORDER BY EventTime DESC
UNION
SELECT top 1 ID, Name, EventTime FROM table
WHERE 
    Name = 'value3' AND EventTime < timeValue3
ORDER BY EventTime DESC

编辑:有多余的或声明,将其删除。

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