运行函数FancyArrowPatch后如何获取坐标？

Question

我在获取由函数FancyArrowPatch绘制的多边形的顶点坐标时遇到问题。

我的代码如下：

import matplotlib

import matplotlib.patches as mpatches

fig, ax = plt.subplots(1)

ax.plot([-199, 592], [0,0], zorder=-1000, c="k",linewidth=0.5)

arrowstyle = mpatches.ArrowStyle.Simple(head_width=14,
                                                tail_width=14,
                                                head_length=8.4)

y = 0

x1=1;x2=393

patch = mpatches.FancyArrowPatch([x1, y], [x2, y],
                                         shrinkA=0.0, shrinkB=0.0,
                                         arrowstyle=arrowstyle)

ax.add_patch(patch)

图片是这样的：

enter image description here

我尝试运行函数patch.get_path_in_displaycoord()，但这返回

(Path(array([[  0.        ,   7.        ],
       [192.30080795,   7.        ],
       [384.60161591,   7.        ],
       [384.60161591,   7.        ],
       [388.80080795,   3.5       ],
       [393.        ,   0.        ],
       [388.80080795,  -3.5       ],
       [384.60161591,  -7.        ],
       [384.60161591,  -7.        ],
       [192.30080795,  -7.        ],
       [  0.        ,  -7.        ],
       [  0.        ,   7.        ],
       [  0.        ,   7.        ]]), array([ 1,  3,  3,  2,  3,  3,  3,  3,  2,  3,  3,  2, 79], dtype=uint8)), True).

很显然，这不是图形中的实际顶点坐标，所以我如何获取图形的顶点坐标？