Question

我需要一个允许将{{[1][value|other]}}转换为Hello {{[1][miss|mr]}} {{[2][Maria|Jon]}}的php正则表达式

我尝试了很多正则表达式，但没有结果，它仅在第一次出现时起作用：

我的文字：Hello $pattern = '/{{\[(\d+)\].+}}/'; $matches = []; preg_match($pattern, $content, $matches); {{2}}

我想要的结果：Array ( [0] => {{[1][miss|mr]}} {{[2][Maria|Jon]}} [1] => 1 )

import { combineReducers } from 'redux-immutable';

import { reducer as formReducer } from 'redux-form';
import appReducer from './appReducer';
import errorReducer from './errorReducer';
import loginReducer from './loginReducer';
import modalReducer from './modalReducer';
import changeRequestReducer from './changeRequestReducer';
import releaseReducer from './releaseReducer';
import releaseReviewReducer from './releaseReviewReducer';
import logoutReducer from './logoutReducer';
import customAvatarReducer from './customAvatarReducer';


    export default combineReducers({
      appReducer,
      errorReducer,
      loginReducer,
      changeRequestReducer,
      releaseReducer,
      modalReducer,
      releaseReviewReducer,
      form: formReducer,
      logoutReducer,
      customAvatarReducer,
    });

给我：

const rootReducer = (state, action) => {
  if (action.type === USER_LOGOUT) {
    const state = undefined;
  }

  return reducers(state, action);
};

const reducers = combineReducers({
  appReducer,
  errorReducer,
  loginReducer,
  changeRequestReducer,
  releaseReducer,
  modalReducer,
  releaseReviewReducer,
  form: formReducer,
  logoutReducer,
  customAvatarReducer,
});

但是我还需要“ 2”

Answer 1

这很简单，只需匹配/使用要删除的字符并捕获要保留的字符即可。

正则表达式演示：https://regex101.com/r/GdIsZX/1/

PHP（https://3v4l.org/L5NSj）

$text = 'Hello {{[1][miss|mr]}} {{[2][Maria|Jon]}}';
echo preg_replace('~\[(\d+)]\[[^]]*]~', '$1', $text);

输出：

Hello \K {{2}}

以上模式并非旨在验证子字符串。重点是有效的广义匹配。如果您需要更严格/准确的模式，则需要通过更好地代表您的挑战的输入来改进问题。

p.s。如果要匹配花括号但不删除它们，则可以使用~{{\K\[(\d+)]\[[^]]*](?=}})~和前瞻。

https://3v4l.org/5oNrL

angular

正则表达式：获取双括号之间的数字

1 个答案: