Question

我有一个运行24/7的批处理文件，以检查某个Programm是否正在运行，如果没有，则启动它。它每10秒钟检查一次，然后这样写一个控制台条目。

    @echo off

    for /L %%n in (1,0,10) do (
    tasklist /nh /fi "imagename eq AutoPrinter.exe" | find /i                 
    "AutoPrinter.exe" >nul && (
    echo %date% %time:~0,8% AutoPrinter already running
    echo %date% %time:~0,8% AutoPrinter already running>>         
    autostarterlog.txt
    ) || (
    start AutoPrinter.exe
    echo %date% %time:~0,8% AutoPrinter started
    echo %date% %time:~0,8% AutoPrinter started >> autostarterlog.txt
    ) 
    timeout /T 10 
    )

但是时间戳没有更新，因此输出看起来像这样

   20.06.2019 10:45:41 AutoPrinter started

   20.06.2019 10:45:41 AutoPrinter already running

   20.06.2019 10:45:41 AutoPrinter already running

   etc...

反正还有时间更新时间戳，以便它们显示实际时间而不总是显示开始时间吗？

Answer 1

@echo off
cls
:start
tasklist /nh /fi "imagename eq AutoPrinter.exe" | find /i                 
"AutoPrinter.exe" >nul && (
   echo %date% %time:~0,8% AutoPrinter already running
   autostarterlog.txt (
      echo %date% %time:~0,8% AutoPrinter already running
   )
) || (
   start AutoPrinter.exe
   echo %date% %time:~0,8% AutoPrinter started
   autostarterlog.txt (
      echo %date% %time:~0,8% AutoPrinter started
   )
) 
timeout /T 10 
goto start

尝试使用goto而不是循环。上面的例子

Answer 2

查看https://stackoverflow.com/a/13809834/11565682后实际上找到了答案在启用延迟扩展并将％更改为！之后这是针对具有相同问题的未来人们的工作准则

    @echo off

    setlocal ENableDelayedExpansion
    for /L %%n in (1,0,10) do (
    tasklist /nh /fi "imagename eq AutoPrinter.exe" | find /i "AutoPrinter.exe" >nul 
    && (
    echo !date! !time:~0,8! AutoPrinter laeuft bereits
    echo !date! !time:~0,8! AutoPrinter laeuft bereits >> autostarterlog.txt
    ) || (
    start AutoPrinter.exe
    echo !date! !time:~0,8! AutoPrinter gestartet
    echo !date! !time:~0,8! AutoPrinter gestartet >> autostarterlog.txt
    ) 
    timeout /T 10 
    )

时间戳不在命令提示符中

2 个答案: