选择除不同的mysql以外的所有值

Question

我是mysql的新手，我很难准备要查询的查询，该查询将返回所有剩余项目（其余项目除外） 例如：

TableName：City

字段是：id,name,population

我想获得所有不相同的城市名称 我正在尝试类似的事情，但这给了我一个错误

SELECT S.CITY FROM STATION AS S LEFT JOIN STATION ON (SELECT DISTINCT(P.CITY) FROM STATION AS P)

有人可以指导我吗

Answer 1

尝试这样的事情：

SELECT city, COUNT(city) AS count
FROM station
GROUP BY city
HAVING COUNT(city) > 1

Answer 2

distinct不是函数而是子句
如果要使用distinct，则可以尝试使用不匹配的子查询left jont

SELECT S.CITY 
FROM STATION AS S 
LEFT JOIN STATION ON ( 
    SELECT DISTINCT CITY 
     FROM STATION 
) T  S.CITY  = T.CITY 
where t.city is null 

但是aso按城市分组，并且jave计数（*）= 1

SELECT CITY 
FROM STATION 
GROUP BY city
having count(*) = 1