我想重现here所见的美丽的摩洛哥马赛克。该代码正在使用Turtle。我想将其翻译为Tkinter。我很幸运地修改了答案here中的代码以绘制到画布上。当然,由于没有从原点绘制任何线,因此缺少很多东西。我不知道该怎么做。一个想法是,我可能会覆盖n个多边形,尽管每个多边形旋转了2 * pi / n度。这仍然留下了将线从原点到每个多边形的起点和终点的问题。我认为这并不能解决所有问题,但这是一个很好的开始。
或者也许更简单地使多边形围绕中心旋转?
from tkinter import *
import math
canvas_width = 400
canvas_height =400
python_green = "#476042"
def polygon(canvas,sides=10, radius=100, rotation=0, translation=None, outline=python_green, fill='White', width = 1):
one_segment = math.pi * 2 / sides
points = [
(math.sin(one_segment * i + rotation) * radius + canvas_width/2,
math.cos(one_segment * i + rotation) * radius + canvas_height/2)
for i in range(sides)]
if translation:
points = [[sum(pair) for pair in zip(point, translation)]
for point in points]
canvas.create_polygon(points, outline=outline, fill='', width=width)
master = Tk()
w = Canvas(master, width=canvas_width, height=canvas_height)
w.pack()
polygon(w,outline='green', width=2)
mainloop()
答案 0 :(得分:0)
您可以使用相同的代码,而无需将其“翻译”为tkinter-您所需要做的就是创建一个canvas
,然后使用RawTurtle
直接在canvas
上绘制
import turtle
import tkinter as tk
root = tk.Tk()
canvas = tk.Canvas(root,width=600,height=600)
canvas.pack()
#below code same from the linked source
myPen = turtle.RawTurtle(canvas) #changed from turtle.Turtle()
myPen.shape("arrow")
myPen.speed(1000)
def drawMosaic(color1, numberOfSides1, size1, color2, numberOfSides2, size2, numberOfIterations):
for i in range(0, numberOfIterations):
myPen.color(color1)
for j in range(0, numberOfSides1):
myPen.forward(size1)
myPen.left(360 / numberOfSides1)
myPen.color(color2)
for k in range(0, numberOfSides2):
myPen.forward(size2)
myPen.left(360 / numberOfSides2)
myPen.left(360 / numberOfIterations)
drawMosaic("#980C6B", 8, 80, "#DD6BB8", 5, 70, 20)
root.mainloop()