Question

我有一个应用程序，其中主用户添加了一个子用户并向他发送电子邮件。我希望该子用户在电子邮件模板中具有一个按钮，该按钮会将他/她引导到“反馈”表单。该反馈表单的url必须带有用户名，因为它具有个人风格。但是我不明白如何传递子用户数据并根据数据保存反馈数据。我将创建一个方案，以使大家更好地理解。

1。。有一个主要用户Chris ，克里斯在其电子邮件列表中添加了一个子用户Leon 。（PS均为常驻邪恶角色）。 2。。克里斯发送电子邮件给莱昂，莱昂将收到该电子邮件，如果他希望他可以单击电子邮件中的“反馈”按钮来提供反馈。 3。。如果Leon点击该按钮，他将被重定向到该URL可能为（www.feedback/Leon.com）之类的页面，将显示以下表格Leon将在其中添加评论并提交。

问题是我如何根据来自子用户模型（PersonData）的信息通过电子邮件表单将Leon的反馈保存在FeedBack模型中。

models.py

class FeedBack(models.Model):
    feedback = models.TextField('Feedback')
    user_feedback = models.ForeignKey(PersonData)


class PersonData(models.Model):

    user_relation = models.ForeignKey(User)
    person_first_name = models.CharField("First Name", max_length=25)
    person_last_name = models.CharField("last Name", max_length=25)
    person_email = models.EmailField("Email", max_length=512)

views.py

# class FeedBackCreateView(CreateView):
#     model = FeedBack
#     template_name = "userfiles/FeedBack.html"

#     def form_valid(self, form):
#         obj = form.save(commit=False)
#         obj.user_feedback_id = self.request.persondata_id
#         obj.save()
#         return redirect("Home-Page")



def feedback(request, username):
    person_data = PersonData.objects.get(person_first_name=username)
    item = FeedBack.objects.all().filter(user_feedback=person_first_name)
    form = FeedBackForm

    if request.method == 'POST':
        if form.is_valid():
            form.save(commit=False)

            profile.employee_name = user
            profile.save()
            return redirect('Home-Page')

    context = {'all_item': all_item}
    return render(request, 'userfiles/AlbumPicsList.html', context)


------------------------------------------------------------------
#This View is from another app called salami. This sends the email
------------------------------------------------------------------

def send_email(request, s_id, pr_id):


    salami_data = SalamiCalculator.objects.get(id=s_id)
    person_data = PersonData.objects.get(id=pr_id)

    context = {'salami_data': salami_data,
               'person_data': person_data}

    subject = "Thank You"
    email_from = settings.EMAIL_HOST_USER  # email from
    to_email = [person_data.person_email]  # email to
    msg = EmailMultiAlternatives()
    msg.from_email = email_from
    msg.to = to_email
    msg.subject = subject
    msg.body = salami_data.thankyou_msg

    html_body = render_to_string("salamifiles\email-thanks.html")
    html_template = get_template("salamifiles\email-thanks.html")
    html_content = html_template.render(context)
    msg.attach_alternative(html_content, "text/html")
    msg.send()
    messages.success(request, ("Email Sent !!"))

    return render(request, 'salamifiles\email-thanks.html', context)

url.py


    url(r'^(?i)Feedback/(?P<user_feedback>\w+)/$',
        AlbumPicturesDetail.as_view(), name='Album-Pictures-View'),

==============================================
Salami URL
==============================================

   url(r'^Congratsmail/(?P<s_id>[0-9]+)/(?P<pr_id>\d+)/$',
        views.send_email, name='Congrats-EMAIL'),

forms.py



class FeedBackForm(forms.ModelForm):

    class Meta:
        model = FeedBack
        fields = ("feedback")

email.html

Have Not Yet modified the email template by adding the button

电子邮件发送模板


{% for i in items %}

<a href={% url 'Congrats-EMAIL' s_id=i.id pr_id=i.realted_person.id %}>Send Mail</a>

{% endfor %}

============================================= ===========================

我希望当克里斯向莱昂发送电子邮件时，莱昂通过单击按钮会被重定向到该页面，该页面具有URL的名称，并且该表单已经知道他是莱昂，以便将数据保存在其ID /名称中。 / p>

Answer 1

我不明白你为什么不能做

class FeedBack(models.Model):
    feedback = models.TextField('Feedback')
    user_feedback = models.ForeignKey(PersonData, related_name="received_feedbacks")
    giver_feedback = models.ForeignKet(PersonData, related_name="given_feedbacks")

Answer 2

我同意@HenryM，您可以添加一个用于与PersonData相关的额外字段。

class FeedBack(models.Model):
    feedback = models.TextField('Feedback')
    user = models.ForeignKey(PersonData, related_name="received_feedbacks")
    giver = models.ForeignKet(PersonData, related_name="given_feedbacks")

然后，您可以像这样使用它：

from django.contrib.auth.decorators import login_required

@login_required
def feedback(request, username):
    person_data = PersonData.objects.get(person_first_name=username)
    item = FeedBack.objects.all().filter(user_feedback=person_first_name)
    form = FeedBackForm(request.POST or None)
    if request.method == 'POST':
        if form.is_valid():
            feedback = form.save(commit=False)
            feedback.user = person_data
            feedback.giver = PersonData.objects.get(user_relation=request.user)
            feedback.save()
            profile.employee_name = user
            profile.save()
            return redirect('Home-Page')

    context = {'form': form}
    return render(request, 'form_which_renders_feedbackform.html', context)

我建议对PersonData中的user_relation字段使用OneToOne关系而不是ForeignKey。这样您就可以简单地通过request.user.persondata访问它。

通过Django电子邮件的用户反馈