my_dict:
{0: {'Id': 'd1', 'name': 'elpato', 'email': '122as@gmail.com'}, 1: {'Id': 'd2', 'name': 'petoka', 'email': 'sss@gmail.com'}}
使用它来获取字典中的名称:
for ids in [v['name'] for v in my_dict.values()]:
#subprocess.call(["...", name])
print(ids)
现在我正在执行此操作,以使用ID中生成的值生成JSON
faker库用于创建随机数据
import faker
import json
import subprocess
for ids in [g['name'] for g in my_dict.values()]:
fake = Faker('en_US')
print(ids)
for ind in ids:
for idx in range(1):
sms = {
"user_id": ind ,
"name": fake.name(),
"email": fake.email(),
"gender": "MALE",
"mother_name": fake.name(),
"father_name": fake.name()
}
f_name = '{}.json'.format(ind)
print(f_name)
with open(f_name, 'w') as fp:
json.dump(sms, fp, indent=4)
我需要的输出:elpato.json,petoka.json。
我得到的输出:
e.json
l.json
p.json
a.json
t.json
o.json
p.json
e.json
t.json
o.json
k.json
a.json
答案 0 :(得分:1)
尝试一下
>>> my_dict = {0: {'Id': 'd1', 'name': 'elpato', 'email': '122as@gmail.com'}, 1: {'Id': 'd2', 'name': 'petoka', 'email': 'sss@gmail.com'}}
>>> ", ".join('{}.json'.format(v) for ik,iv in d.items() for k,v in iv.items() if k == 'name')
'elpato.json, petoka.json' # output in string form
替换为(完整代码)
import faker
import json
import subprocess
my_dict = {0: {'Id': 'd1', 'name': 'elpato', 'email': '122as@gmail.com'}, 1: {'Id': 'd2', 'name': 'petoka', 'email': 'sss@gmail.com'}}
f_names = [(ik, '{}.json'.format(v)) for ik,iv in my_dict.items() for k,v in iv.items() if k == 'name']
for values in f_names:
fake = Faker('en_US')
ind,f_name = [*values]
sms = {
"user_id": ind ,
"name": fake.name(),
"email": fake.email(),
"gender": "MALE",
"mother_name": fake.name(),
"father_name": fake.name()
}
with open(f_name, 'w') as fp:
json.dump(sms, fp, indent=4)
答案 1 :(得分:0)
尝试一下:
my_dict = {0: {'Id': 'd1', 'name': 'elpato', 'email': '122as@gmail.com'}, 1: {'Id': 'd2', 'name': 'petoka', 'email': 'sss@gmail.com'}}
for k, v in my_dict.items():
print(my_dict[k]['name']+".json")
或者,尝试下面的代码代替print(my_dict[k]['name']+".json")
:
print('{}.json'.format(my_dict[k]['name']))
您也可以尝试以下方法:
for value in my_dict.values():
print('{}.json'.format(value['name']))
输出:
elpato.json
petoka.json
答案 2 :(得分:0)
In [14]: ', '.join(f"{i['name']}.json" for i in my_dict.values())
Out[14]: 'elpato.json, petoka.json'
另一个选择是使用:
You can use print(f"{f_name}.josn", end = ', ')