我正在尝试使用$filepath='http://localhost/mb/inc/tmp/liberty/xml_invoice.zip'
header('Content-Description: File Transfer');
header('Content-Type: application/octet-stream');
header('Content-Disposition: attachment; filename="test.zip');
header('Content-Transfer-Encoding: binary');
header('Expires: 0');
header('Cache-Control: must-revalidate, post-check=0, pre-check=0');
header('Pragma: public');
header('Content-Length: ' . filesize($filepath));
ob_clean();
flush();
readfile($filepath);
exit();
下载一个zip文件。但是它返回一些特殊字符。
我尝试了以下代码。
�Q�s�+k�X�ߡB�R�EE����m��@;Ok����A���R�2vZ�j�F�Mo� C�
当我运行这段代码时,我得到的输出像一些特殊字符一样。
{{1}}
答案 0 :(得分:0)
如果要传递ZIP文件,则还需要使用正确的MIME内容类型!
def solve(n):
l=range(1,n+1)
length = n
items=l
def inner(ix=[]):
do_yield = len(ix) == length - 1
for i in range(0, length):
if i in ix: #avoid duplicates
continue
if do_yield:
yield tuple([items[y] for y in ix + [i]])
else:
for p in inner(ix + [i]):
yield p
t=inner()
#rr=list(pp(list(range(1,n+1)),4))
#l=''.join(l)
#=list(l)
#t=pp(list(l))
#print(t)
result=0
for j in list(t):
#print("j",j)
if j[0]<j[1] and j[1]<j[2] and j[2]<j[3]:
#result=j[0]
#for k in j[1:]:
#result=self.gcd(result,k)
result=result+1
#su=su+self.fast(result,4)
print(result%1000000007)
#ob=Solution()
for i in range(int(input())):
n=input()
n=int(n)
solve(n)
答案 1 :(得分:0)
尝试一下:提供zip文件的路径。
$filepath = "/path/to/some_file.zip";
$file_name = basename($filepath);
header("Content-Type: application/zip");
header("Content-Disposition: attachment; filename=$file_name");
header("Content-Length: " . filesize($filepath));
readfile($filepath);
exit;