在modules.js
中,我有以下代码:
module.exports = {
BookingHotel: function() {
this.getId = function(id) {
return "Hello World";
},
this.getAll = function() {
return "Hello World";
}
},
BookingFlight: function() {
this.book = function() {
return "Hello World";
}
},
}
modules.js
文件太大,难以维护。
如何将BookingHotel
和BookingFlight
分成单独的文件,并像当前一样导出它们?
答案 0 :(得分:1)
为modules.js
中的每次导出制作一个单独的JavaScript文件,并使每个文件导出一个功能,然后只需要每个文件并重新导出如下功能即可:
注意:单个文件的名称并不重要,只要它们与modules.js
中使用的文件名一致即可。
BookingHotel.js:
module.exports = {
BookingHotel: function() {
// Your code here
}
};
BookingFlight.js:
module.exports = {
BookingFlight: function() {
// Your code here
}
};
modules.js:
// Get the exports from BookingHotel.js
var BookingHotelExports = require("./BookingHotel.js");
// Get the exports from BookingFlight.js
var BookingFlightExports = require("./BookingFlight.js");
// Combine the individual exports from the two required modules into a new exports variable for this module.
module.exports = {
// BookingHotel is a property of the module.exports object from BookingHotel.js.
BookingHotel: BookingHotelExports.BookingHotel,
// Same here, but from BookingFlight.js.
BookingFlight: BookingFlightExports.BookingFlight
};
答案 1 :(得分:1)
为对象创建单独的文件:
BookingHotel.js
BookingFlight.js
从相应文件中导出对象:
BookingHotel.js:
export default var BookingHotel = function() {
this.getId = function(id) {
return "Hello World";
},
this.getAll = function() {
return "Hello World";
}
}
BookingFlight.js:
export default var BookingFlight = function() {
this.book = function() {
return "Hello World";
}
}
modules.js
文件中,并将它们添加到导出对象中:modules.js:
import BookingHotel from 'BookingHotel.js';
import BookingFlight from 'BookingFlight.js';
module.exports = {
BookingHotel: BookingHotel,
BookingFlight: BookingFlight
};