Question

8 这是我的查询

$query = DB::table('hr_employees')
            ->select(DB::raw('hr_employees.id', 'hr_employees.employee_id_number', 'hr_employees.first_name', 'GROUP_CONCAT(hr_employee_daily_attendances.first_in SEPARATOR ', ') as tags'))
            ->join('hr_employee_daily_attendances', function ($join) {
                $join->on('hr_employees.employee_id_number', '=', 'hr_employee_daily_attendances.employee_id_number');
            });

        return $query->paginate();

此查询仅返回hr_employee.id。我需要获取所有指定的列值

有人可以帮助我吗？预先感谢

Answer 1

我通过此查询解决了该问题

$query = DB::table('hr_employees')
            ->select(DB::raw('hr_employees.id, hr_employees.employee_id_number, hr_employees.first_name, GROUP_CONCAT(hr_employee_daily_attendances.first_in SEPARATOR ", ") as month_days'))
            ->join('hr_employee_daily_attendances', function ($join) {
                $join->on('hr_employees.employee_id_number', '=', 'hr_employee_daily_attendances.employee_id_number');
            })
            ->groupBy('hr_employee_daily_attendances.employee_id_number')
            ->groupBy('hr_employees.id')
            ->groupBy('hr_employees.employee_id_number')
            ->groupBy('hr_employees.first_name');

        return $query->paginate(10);

Answer 2

我从未在DB :: raw命令之外看到SELECT。尝试将SELECT语句移入DB :: raw

Laravel选择带有GROUP_CONCAT列的表列

2 个答案: