我编写了一个代码,用于从JSON行读取信息到SQL中的表:
declare @pJSON varchar(max) = '
{
"School": "MiddleSchool",
"Password": "SchoolPassword",
"Attributes": [
{
"Type": "Exam",
"Value": "1"
},
{
"Type": "Class",
"Value": "11b"
},
{
"Type": "Math",
"Value": [
{
"ExamDate": "2019-01-01",
"Points": 100,
"Grade": 10,
"Notes": "Good"
}
]
}
]
} '
select ExamDate, Points, Grade, Notes
from OPENJSON(@pJSON, N'$.Attributes[2].Value')
cross apply openjson ([Value])
with
(
ExamDate date,
Points int,
Grade int,
Notes varchar(max)
) as [value]
代码工作正常,但我真的很讨厌N'$.Attributes[2].Value'
部分。考试信息可以排在第一,第二,第三位,因此[2]
对我而言并不是很有效。您对我有什么建议,我如何改进此代码?谢谢!
答案 0 :(得分:1)
您可以使用JSON_QUERY
:
select ExamDate, Points, Grade, Notes
from OPENJSON(JSON_QUERY(@pJSON, N'$.Attributes'))
with
(
ExamDate date N'$.Value[0].ExamDate', -- here 0 because Value is array too
Points int N'$.Value[0].Points',
Grade int N'$.Value[0].Grade',
Notes varchar(max) N'$.Value[0].Notes'
) as [value]
WHERE ExamDate IS NOT NULL;
在最初的问题中,只有一门考试。如果数组可能包含的代码不止一个,则应进行调整:
SELECT s2.[key]
,ExamValue = JSON_VALUE(s2.value, '$.ExamDate')
,Points = JSON_VALUE(s2.value, '$.Points')
,Grade = JSON_VALUE(s2.value, '$.Grade')
,Notes = JSON_VALUE(s2.value, '$.Notes')
FROM OPENJSON(JSON_QUERY(@pJSON, N'$.Attributes')) s
CROSS APPLY OPENJSON(JSON_QUERY(s.value, N'$.Value')) s2;
-- or
SELECT [value].*
FROM OPENJSON(JSON_QUERY(@pJSON, N'$.Attributes'))
CROSS APPLY OPENJSON(JSON_QUERY(value, N'$.Value'))
with
(
ExamDate date N'$.ExamDate',
Points int N'$.Points',
Grade int N'$.Grade',
Notes varchar(max) N'$.Notes'
) as [value];