Question

下面是我采样的两个类。不使用元组；我想直接从第一个列表向第二个结果列表发送查询。

编码失败的部分显示为转换操作。

感谢您的宝贵时间和答复。

        static void Main(string[] args)
    {

        List<liste> personel = new List<liste>{

            new liste { PersonId = 1, Name = "Burak", Surname = "Şenyurt", City = "İstanbul", Salary = 890 },
            new liste { PersonId = 2, Name = "Maykıl", Surname = "Cordın", City = "Chicago", Salary = 930 },
            new liste { PersonId = 3, Name = "Şakiyıl", Surname = "Oniyıl", City = "Los Angles", Salary = 986 },
            new liste { PersonId = 4, Name = "Ümit", Surname = "Oniyıl", City = "Los Angles", Salary = 1035 },
            new liste { PersonId = 5, Name = "Mehmet", Surname = "Zaferoğlu", City = "Los Angles", Salary = 1265 },
            new liste { PersonId = 6, Name = "Hasan", Surname = "Orkun", City = "Los Angles", Salary = 1435 },
            new liste { PersonId = 7, Name = "Raşit", Surname = "Mesut", City = "Los Angles", Salary = 1469 },
            new liste { PersonId = 8, Name = "Hamdi", Surname = "Tanpınar", City = "Los Angles", Salary = 1535 },
            new liste { PersonId = 9, Name = "Şevki", Surname = "Çapkın", City = "Los Angles", Salary = 1636 },
            new liste { PersonId = 10, Name = "Özhun", Surname = "Bozkurt", City = "Los Angles", Salary = 1839 }
        };
        double resAVG = personel.Select(x => x.Salary).Average();
        List<Sonuc> reportResult = GetReport(personel,resAVG);
    }

静态方法

        public static List<Sonuc> GetReport(List<liste> listePersonel , double resAVG)
    {
        List<Sonuc> result = (from e in listePersonel
                      where e.Salary >= resAVG
                      orderby e.Salary descending
                    //select new Tuple<string, string, double>(e.Name, e.Surname, e.Salary)).ToList<Tuple<string, string, double>>();
        select new List<Sonuc>(e.Name, e.Surname, e.Salary)).ToList<Sonuc>(result.ToList());

        return result;
    }

普通班

   public class liste
{
    public int          PersonId        { get; set; }
    public string       Name            { get; set; }
    public string       Surname         { get; set; }
    public string       City            { get; set; }
    public double       Salary          { get; set; }

    public override string ToString()
    {
        return $"PersonId : {PersonId}\t\tName , Surname {Name} , {Surname}\t\t\tSalary : {Salary}";
    }
}

结果类

    public class Sonuc
{
    public string       Name            { get; set; }
    public string       Surname         { get; set; }
    public double       Salary          { get; set; }

    public Sonuc(string Name , string Surname, double Salary)
    {
        this.Name = Name;
        this.Surname = Surname;
        this.Salary = Salary;
    }

    public override string ToString()
    {
        return $"Name, SurName : {this.Name} ,   {this.Surname}\t\t\tSalary : {this.Salary}";
    }
}

Answer 1

您正试图通过传递if (telephonyManager != null && input.equals(MMI_IMEI_DISPLAY)) { int labelResId = (telephonyManager.getPhoneType() == TelephonyManager.PHONE_TYPE_GSM) ? R.string.imei : R.string.meid; List<string> deviceIds = new ArrayList<string>(); if (TelephonyManagerCompat.getPhoneCount(telephonyManager) > 1 && CompatUtils.isMethodAvailable(TelephonyManagerCompat.TELEPHONY_MANAGER_CLASS, "getDeviceId", Integer.TYPE)) { for (int slot = 0; slot < telephonyManager.getPhoneCount(); slot++) { String deviceId = telephonyManager.getDeviceId(slot); if (!TextUtils.isEmpty(deviceId)) { deviceIds.add(deviceId); } } } else { deviceIds.add(telephonyManager.getDeviceId()); } AlertDialog alert = new AlertDialog.Builder(context) .setTitle(labelResId) .setItems(deviceIds.toArray(new String[deviceIds.size()]), null) .setPositiveButton(android.R.string.ok, null) .setCancelable(false) .show(); return true; } return false; }，const response = 'var x = [["data","like", "this"],["and","like","this"]]' const output = JSON.parse(response.substring(response.indexOf('=') + 1)) console.log(output)和List<T>来构造string的实例。 string没有使用这些参数的构造函数。另外，在分配double之前不能使用它。

相反，您应该将List<T>中的每个项目投影到result的单个实例中，然后将其枚举到listePersonel中。

Sounc

C＃LINQ返回通用列表<T>

1 个答案: