将IOB格式的数据列表转换为简单的IOB格式的数据

Question

我是nlp的初学者，想从句子列表中生成IOB格式。

我具有以下格式的IOB格式的数据：

[('in', 'O'), ('this', 'B-DATE'), ('week', 'I-DATE'), ('how', 'O'), ('many', 'O'), ('activities', 'O'), ('do', 'O'), ('i', 'O'), ('have', 'O'), ('?', 'O')]

预期输出为

in O
this B-DATE
week I-DATE
how O
many O
activities O
do O
i O
have O
? O

Answer 1

如果您需要一个仅包含由初始列表的成员组成的字符串的新list，则可以尝试以下操作：

initial = [('in', 'O'), ('this', 'B-DATE'), ('week', 'I-DATE'), ('how', 'O'), ('many', 'O'), ('activities', 'O'), ('do', 'O'), ('i', 'O'), ('have', 'O'), ('?', 'O')]

modified = [' '.join(z) for z in initial]

for row in modified:
    print(row)

输出：

in O
this B-DATE
week I-DATE
how O
many O
activities O
do O
i O
have O
? O