我不是Spring,JPA,Hibernate或MySql的专家。 但是,我正在使用所有支持RESTful调用的Web服务。 我正在用Spring构建一个商店管理应用程序后端。 我目前的实体是StoreModel,StoreUserModel,StoreUserRoleModel和StoreUserAuthModel。
我之间建立了双向关系(OneToMany和ManyToOne) StoreModel-StoreUserAuthModel, StoreUserMode-StoreUserAuthModel和 StoreUserRoleMode-StoreUserAuthModel。
尽管StoreUserAuthModel中有外键字段storeid,roleid和userid,但我不希望使用外键约束。
现在,所有四个表都具有isdeleted列,以实现软删除。 我懒洋洋地取缔这些协会。但是,无论何时我查询关联,我都不希望被软删除的值。
我想知道是否可以在StoreUserAuthModel实体中同时使用@Where注释和@ManyToOne注释?
问题与How to use @Where in Hibernate不同,因为我的问题是与ManyToOne批注有关,而我对OneToMany使用了where批注
@Entity
@Table(name = "store")
public class StoreModel {
@NotBlank
private String name;
@NotBlank
private String address;
@NotBlank
private String city;
@NotBlank
private String phone;
@JsonIgnore
@OneToMany(fetch = FetchType.LAZY)
@JoinColumn(name = "storeid", foreignKey = @ForeignKey(name="none", value = ConstraintMode.NO_CONSTRAINT ))
@Where(clause="isdeleted = 0")
private List<StoreUserAuthModel> authList = new ArrayList<StoreUserAuthModel>();
...
}
@Entity
@Table(name = "storerole")
public class StoreRoleModel {
@NotBlank
private String name;
@NotBlank
private Integer rolehierarchy;
@JsonIgnore
@OneToMany(fetch = FetchType.LAZY)
@JoinColumn(name = "roleid", foreignKey = @ForeignKey(name="none", value = ConstraintMode.NO_CONSTRAINT ))
@Where(clause="isdeleted = 0")
private List<StoreUserAuthModel> authList = new ArrayList<StoreUserAuthModel>();
...
}
@Entity
@Table(name = "storeuser")
public class StoreUserModel{
@NotBlank
@Column(unique = true)
private String username;
@Email
@Column(unique = true)
private String useremail;
@JsonIgnore
@OneToMany(fetch = FetchType.LAZY)
@JoinColumn(name = "userid", foreignKey = @ForeignKey(name="none", value = ConstraintMode.NO_CONSTRAINT ))
@Where(clause="isdeleted = 0")
List<StoreUserAuthModel> userAuthList = new ArrayList<StoreUserAuthModel>();
...
}
@Entity
@Table(name = "storeuserauth",
uniqueConstraints = @UniqueConstraint(columnNames = {"storeid", "roleid", "userid"}))
public class StoreUserAuthModel {
@NotNull
Long storeid;
@NotNull
Long roleid;
@NotNull
Long userid;
// Using @where to filter out the soft deleted storeuser
@JsonIgnore
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name="userid", foreignKey = @ForeignKey(name="none", value = ConstraintMode.NO_CONSTRAINT ),insertable = false, updatable = false )
@Where(clause="isdeleted = 0")
private StoreUserModel storeuser;
// Using @where to filter out the soft deleted store
@JsonIgnore
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name="storeid", foreignKey = @ForeignKey(name="none", value = ConstraintMode.NO_CONSTRAINT ),insertable = false, updatable = false )
@Where(clause="isdeleted = 0")
private StoreModel store;
// Using @where to filter out the soft deleted role
@JsonIgnore
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name="roleid", foreignKey = @ForeignKey(name="none", value = ConstraintMode.NO_CONSTRAINT ),insertable = false, updatable = false )
@Where(clause="isdeleted = 0")
private StoreRoleModel role;
...
}
// In the controller, Following code shows how I plan to use
Optional<StoreUserModel> aUser = storeUserRepository.findByUseremailAndIsdeleted(zUserMail), 0);
if(aUser.isPresent()) {
// The user was found!!!
// Testing...
// Getting the User Auth List (that will filter out the soft deleted auths)
List<StoreUserAuthModel> authList = aUser.get().getUserAuthList();
for(StoreUserAuthModel auth :authList) {
StoreModel store = auth.getStore();
// here both soft deleted store as well as normal stores are shown.
// ie where clause on store relation is not working!!
logger.debug("Store is "+store.getName());
}
}
...
现在,所有与ID匹配的商店行都在列表中。 预期结果也应该在where子句中应用
我打开了休眠5.3.9的日志记录 触发选择查询时没有where子句
答案 0 :(得分:0)
@Where注释对ToOne关系没有影响。但是,除了在引用中添加@Where之外,您还可以在实体上使用@Where:
@Where(clause="isdeleted = 0")
@Entity
@Table(name = "storerole")
public class StoreRoleModel {
这样,Hibernate将不会加载StoreRoleModel的已删除实体。