Question

我正在尝试过滤具有子数组的数组。我想按子数组过滤我的数组我的数组看起来像这样：

 var Branches = [
            {
                Name: 'branch1',
                Screens: [
                    {
                        Name: 'Screen1',
                        Player: {
                            Status: 0
                        }
                    },
                    {
                        Name: 'Screen2',
                        Player: {
                            Status: 1
                        }
                    }
                ]
            },
            {
                Name: 'branch2',
                Screens: [
                    {
                        Name: 'Screen1',
                        Player: {
                            Status: 0
                        }
                    },
                    {
                        Name: 'Screen2',
                        Player: {
                            Status: 1
                        }
                    }
                ]
            }]

我已经使用linq.js进行了尝试

var param = 1
var result = Enumerable.From(Branches).Where(function (d) {

                return (d.Screen.some(x => x.Player.Status === param))

            }).ToArray();

但是此代码olso从每个分支获得状态0

我只想从每个分支获取状态= 1

预期：

[
            {
                Name: 'branch1',
                Screens: [
                    {
                        Name: 'Screen2',
                        Player: {
                            Status: 1
                        }
                    }
                ]
            },
            {
                Name: 'branch2',
                Screens: [
                    {
                        Name: 'Screen2',
                        Player: {
                            Status: 1
                        }
                    }
                ]
            }

        ]

谢谢;）

Answer 1

var Branches = [
  {
    Name: "branch1",
    Screens: [
      {
        Name: "Screen1",
        Player: {
          Status: 0
        }
      },
      {
        Name: "Screen2",
        Player: {
          Status: 1
        }
      }
    ]
  },
  {
    Name: "branch2",
    Screens: [
      {
        Name: "Screen1",
        Player: {
          Status: 0
        }
      },
      {
        Name: "Screen2",
        Player: {
          Status: 1
        }
      }
    ]
  }
];
var param = 1;
console.log(Branches.reduce( (p, c) => ((c.Screens = c.Screens
    .filter(s => s.Player.Status == param)).length && p.push(c), p), []
));

Answer 2

您可以映射对象并过滤Screens。

var branches = [{ Name: 'branch1', Screens: [{ Name: 'Screen1', Player: { Status: 0 } }, { Name: 'Screen2', Player: { Status: 1 } }] }, { Name: 'branch2', Screens: [{ Name: 'Screen1', Player: { Status: 0 } }, { Name: 'Screen2', Player: { Status: 1 } }] }],
    wanted = 1,
    result = branches.map(({ Screens, ...o }) => ({ ...o, Screens: Screens.filter(({ Player: { Status } }) => Status === wanted) }));

console.log(result);

Answer 3

使用linq.js，您需要将其查看为选择具有一组经过过滤的屏幕的分支。您可能不想修改现有项目，因此应该创建新项目。

let status = 1;
let result = Enumerable.From(Branches)
    .Select(({Screens, ...rest}) => ({
        Screens: Enumerable.From(Screens)
            .Where(({Player:{Status}}) => Status === status)
            .ToArray(),
        ...rest
    })).ToArray();

尽管妮娜（Nina）表示，您实际上并不需要它，因为Array.map和Array.filter可以解决这个问题。

筛选子阵列

3 个答案: