Question

如何舍入秒数：

介于1 sec - 59 sec至1 minute

在1 min 1 sec-1 min 59 sec之间->舍入到2 m

在1h 2 min 1 sec-2 min 59 sec之间->舍入到1h 3 m吗？

在2 min 1 sec-2 min 59 sec之间->舍入到3 m吗？

我使用库“ moment”

预期效果：

Date2-date1 =结果四舍五入为整分钟。

date2-date1 = 30 s->舍入为1 m

date2-date1 = 5s->舍入为1 m

date2-date1 = 1m 10s->舍入为2 m

javascript或moment.js库中可能有一种方法

a = (d1, d2) => {
  let b= moment(d2).diff(d1,"minutes",true)

  return  Math.round(b) * 60; 
}

不同的1m 20 s->舍入到2m->没关系

5s不同->不要舍入到1 m // problem here

Answer 1

您可以在秒数上增加59秒，然后增加分钟数。

console.log([0, 1, 59, 60, 61].map(v => Math.floor((v + 59) / 60)));

Answer 2

尝试一下，虽然有点基本，但可以使用：

const MAX_MIN_SEC = 60;
const MAX_HRS = 24;
const MAX_DAYS = 365;
var date1 = new Date(2018, 07, 00, 00, 00, 00);
var date2 = new Date(2018, 07, 00, 00, 00, 05);
var msec = date2 - date1;
var seconds = Math.floor(msec / 1000);
var mins = Math.floor(seconds / MAX_MIN_SEC);
var hrs = Math.floor(mins / MAX_MIN_SEC);
var days = Math.floor(hrs / MAX_HRS);
var yrs = Math.floor(days / MAX_DAYS);
seconds = seconds % MAX_MIN_SEC;
mins = mins % MAX_MIN_SEC; 
hrs = hrs % MAX_HRS;
days = days % MAX_DAYS;
if (seconds > 0){
  seconds = 0;
  mins++;
}
if (mins >= MAX_MIN_SEC){
  mins = 0;
  hrs++;
}
if (hrs >= MAX_HRS){
  hrs = 0;
  days++;
}
if (days >= MAX_DAYS){
  days = 0;
  yrs++;
}
Console.log(yrs + " year/s, " + days + " day/s, " + hrs + " hour/s, " + mins + " minute/s," + seconds + " second/s");

结果：

0 years, 0 days, 0 hours, 1 minutes,0 seconds

Answer 3

您正在搜索Math.ceil()

const a = (d1, d2) => {
  let b = moment(d2).diff(d1, "minutes", true)
  return Math.ceil(b)
}

console.log(a('2019-07-05 10:43:18', '2019-07-05 10:43:18'))
console.log(a('2019-07-05 10:43:18', '2019-07-05 10:43:59'))
console.log(a('2019-07-05 10:43:18', '2019-07-05 10:44:59'))

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.24.0/moment.js" integrity="sha256-H9jAz//QLkDOy/nzE9G4aYijQtkLt9FvGmdUTwBk6gs=" crossorigin="anonymous"></script>

更新

Moment直到现在才支持duration().format()。但是您可以尝试这种解决方法（如果需要，您需要处理数天）

const a = (d1, d2) => {
  let b = moment(d2).diff(d1, "minutes", true)
  let d = moment.duration({
    minutes: Math.ceil(b)
  })
  return moment(d._data).format('H[h] m[m]').replace(/^0h\s|\s0m/, '')
}

console.log(a('2019-07-05 10:43:18', '2019-07-05 10:43:18'))
console.log(a('2019-07-05 10:43:18', '2019-07-05 10:43:59'))
console.log(a('2019-07-05 10:43:18', '2019-07-05 20:44:59'))

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.24.0/moment.js" integrity="sha256-H9jAz//QLkDOy/nzE9G4aYijQtkLt9FvGmdUTwBk6gs=" crossorigin="anonymous"></script>

或使用 moment-duration-format

const a = (d1, d2) => {
  let b = moment(d2).diff(d1, "minutes", true)
  
  return moment.duration({
    minutes: Math.ceil(b)
  }).format("d[d] h[h] m[m]", { trim: "both" });
}

console.log(a('2019-07-05 10:43:18', '2019-07-05 10:43:18'))
console.log(a('2019-07-05 10:43:18', '2019-07-05 10:43:59'))
console.log(a('2019-07-05 10:43:18', '2019-07-07 20:44:59'))

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.24.0/moment.js" integrity="sha256-H9jAz//QLkDOy/nzE9G4aYijQtkLt9FvGmdUTwBk6gs=" crossorigin="anonymous"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment-duration-format/2.3.2/moment-duration-format.min.js" integrity="sha256-M2KULKSJyw+G0068JiMlM9GX4XpLdUButSzBqntKDZM=" crossorigin="anonymous"></script>

Answer 4

Sjoerd Loeve对this possible duplicate的回答包括一个指向这样做的干净方法的链接https://jsfiddle.net/2wqs4o0v/3：

var now = new moment(new Date());

if (now.seconds() > 0) {
    now.add('minutes', 1);
}

JSFiddle不会导入矩（SO也不会），但这看起来可以工作，并且如果您想将时间取整为0秒但大于0毫秒，则可以添加&& now.milliseconds() > 0。 / p>

如何将数字四舍五入为整分钟？

4 个答案: