Question

我正在尝试检查字符串是否遵循特定的模式。字符串必须遵循模式[check（id（“ numeric only”），“指定关键字的1”）]，其中指定关键字= D，D5，W1，W2，W3，W4，W5，W6，W0，M ，Q1，Q2，Q3，H1，H2，H3，H4，H5，H6，Y1，Y2，A2，Y4，Y5，A3，Y7，Y8，A4，YA，YB，A1。

freq <- c("D", "D5", "W1", "W2", "W3", "W4", "W5", "W6", "W0", "M", "Q1", 
           "Q2", "Q3", "H1", "H2", "H3", "H4", "H5", "H6", "Y1", "Y2", "A2", 
           "Y4", "Y5", "A3", "Y7", "Y8", "A4", "YA", "YB", "A1")
> grepl("\\<check\\(id\\(+\\d+\\),\\bA1\\b|\\bA2\\b\\)\\>", "check(id(32131241w),A1)")
[1] FALSE

> grepl("\\<check\\(id\\(+\\d+\\),\\bA1\\b|\\bA2\\b\\)\\>", "check(id(32131241),A1)")
[1] TRUE

> grepl("\\<check\\(id\\(+\\d+\\),\\b", paste0(freq, collapse = "\\b|\\b"), "\\b\\)\\>", "check(id(32131241w),A1)")
[1] FALSE

> grepl("\\<check\\(id\\(+\\d+\\),\\b", paste0(freq, collapse = "\\b|\\b"), "\\b\\)\\>", "check(id(32131241),A1)")
[1] FALSE

第一个，第二个和第三个输出是正确的结果，但是我期望第四个结果是TRUE，但是R返回FALSE。

Answer 1

#Second line from you
grepl("\\<check\\(id\\(+\\d+\\),\\bA1\\b|\\bA2\\b\\)\\>", "check(id(32131241),A1)")
#TRUE

#Change A1 to A2
grepl("\\<check\\(id\\(+\\d+\\),\\bA1\\b|\\bA2\\b\\)\\>", "check(id(32131241),A2)")
#FALSE

#Adding surrounding <>
grepl("\\<check\\(id\\(+\\d+\\),\\bA1\\b|\\bA2\\b\\)\\>", "<check(id(32131241),A2)>")
#FALSE

#Adding perl=TRUE
grepl("\\<check\\(id\\(+\\d+\\),\\bA1\\b|\\bA2\\b\\)\\>", "<check(id(32131241),A2)>", perl=TRUE)
#TRUE

#Add () arround |
grepl("\\<check\\(id\\(+\\d+\\),(\\bA1\\b|\\bA2\\b)\\)\\>", "<check(id(32131241),A2)>", perl=TRUE)
#TRUE

#Here you have to add one additional paste
grepl(paste0("\\<check\\(id\\(+\\d+\\),(\\b", paste0(freq, collapse = "\\b|\\b"), "\\b)\\)\\>"), "<check(id(32131241),A1)>", perl=TRUE)
#TRUE

R grepl返回不同的结果

1 个答案: