我已经弄清楚了如何检测矩形和图像的冲突,但是我遇到的问题是当我调用该方法来重新定位图像时,它连续连续执行10次,然后将不再起作用。
我正在用JavaFX开发我的第一款游戏。我正在尝试制作基本的蛇游戏,但一直无法弄清蛇与它碰撞后重新放置食物的问题。
public class Main extends Application {
Stage window;
Scene mainScene;
private final int WIDTH = 500;
private final int HEIGHT = 500;
Timeline timeline;
private Direction action = Direction.RIGHT;
private Rectangle snakeHead;
private final int speed = 3;
private int xSpeed = 3;
private int ySpeed = 3;
private int snakeW = 20;
private int snakeH = 20;
private BoundingBox snakeBox;
private BoundingBox foodBox;
private ImageView food;
private Random rand = new Random();
private double foodX;
private double foodY;
enum Direction {
LEFT,RIGHT,UP,DOWN;
}
private Parent createContent(){
Pane root = new Pane();
//food = new Food();
food = new ImageView(new Image("resources/apple.png"));
food.setFitHeight(25);
food.setFitWidth(25);
food.setPreserveRatio(true);
newFood();
foodBox = new BoundingBox(foodX,foodY,20,20);
snakeHead = new Rectangle(snakeW,snakeH);
snakeHead.setTranslateX(200);
snakeHead.setTranslateY(200);
snakeBox = new BoundingBox(snakeHead.getTranslateX(),snakeHead.getTranslateY(),snakeW,snakeH);
timeline = new Timeline(new KeyFrame(Duration.millis(16), e-> {
//Snake movement
if(action == Direction.LEFT) {snakeHead.setTranslateX(snakeHead.getTranslateX() - xSpeed);}
if(action == Direction.RIGHT) {snakeHead.setTranslateX(snakeHead.getTranslateX() + xSpeed);}
if(action == Direction.UP) {snakeHead.setTranslateY(snakeHead.getTranslateY() - ySpeed);}
if(action == Direction.DOWN) {snakeHead.setTranslateY(snakeHead.getTranslateY() + ySpeed);}
//Stops snake at edges of screen
if(snakeHead.getTranslateX() <= 0){
xSpeed = 0;
if(action == Direction.RIGHT){xSpeed = speed;}
}
if(snakeHead.getTranslateX() >= WIDTH - snakeW){
xSpeed = 0;
if(action == Direction.LEFT){xSpeed = speed;}
}
if(snakeHead.getTranslateY() <= 0){
ySpeed = 0;
if(action == Direction.DOWN){ySpeed = speed;}
}
if(snakeHead.getTranslateY() >= HEIGHT - snakeH){
ySpeed = 0;
if(action == Direction.UP){ySpeed = speed;}
}
//TODO: Detect Collisions
if(foodBox.intersects(snakeHead.getTranslateX(),snakeHead.getTranslateY (),snakeW,snakeH)){
newFood();
System.out.println("Collision");
}
}));
timeline.setCycleCount(Timeline.INDEFINITE);
root.getChildren().addAll(snakeHead,food);
return root;
}
private void newFood() {
foodX = rand.nextInt(500);
foodY = rand.nextInt(500);
food.setTranslateX(foodX);
food.setTranslateY(foodY);
System.out.println("X " + foodX);
System.out.println("Y " + foodY);
}
private void startGame() {
timeline.play();
}
private void stopGame() {
timeline.stop();
}
@Override
public void start(Stage primaryStage) throws Exception{
window = primaryStage;
mainScene = new Scene(createContent(),WIDTH,HEIGHT);
mainScene.setOnKeyPressed(e-> {
switch(e.getCode()) {
case UP: action = Direction.UP; break;
case DOWN: action = Direction.DOWN; break;
case LEFT: action = Direction.LEFT; break;
case RIGHT: action = Direction.RIGHT; break;
}
});
window.setTitle("Snake");
window.setResizable(false);
window.setScene(mainScene);
window.show();
startGame();
}
public static void main(String[] args) {
launch(args);
}
}
我要寻找的是矩形碰到重新定位的苹果时。我已经为此苦苦挣扎了一段时间,不知道该怎么办。我还是一个相当新的程序员。
答案 0 :(得分:1)
您可以检查蛇与食物的boundsInParent的交集。
if(food.getBoundsInParent().intersects(snakeHead.getBoundsInParent())){
newFood();
System.out.println("Collision");
}