Question

我正在开发一个Android应用程序，该应用程序汇总了从金融服务提供商发送给客户的短信，每次用户进行交易时，短信都会作为通知发送。这是示例消息

[-ZAAD SHILLING-] Ref：1141125019 SLSH4,000发送给AXMED XASAN WARSAME（634458520）在19/05/12 22:33:03，您的余额为 SLSH44,222.62。

所以我想提取此消息的几个部分，例如

Ref：1141125019
发送量：SLSH4,000
收件人名称：AXMED XASAN WARSAME
收件人电话：634458520
日期：19/05/12
时间：22:33:03 余额：SLSH44,222.62

我已经将文本消息显示在列表视图中，现在我想对其进行自定义，我不希望整个消息都出现，我只希望上面提到的部分出现。

这是示例代码

  if (Data.contains("Ref:")){
                    String[] Tx = Data.split("Ref:");
                    String TxID = Tx[1];
}

Answer 1

使用正则表达式（regex）可能可以最好地解决此问题

使用正则表达式可以根据模式匹配字符串，并从字符串中提取信息。

    public static void main(String[] args) {
        String data = "( [-ZAAD SHILLING-] Ref:1141125019 SLSH4,000 sent to AXMED XASAN WARSAME(634458520) at 12/05/19 22:33:03, Your Balance is SLSH44,222.62. )";

        String headerReg = "\\[-([a-zA-Z\\s]+?)-]";
        String refReg = "Ref:([0-9]+)";
        String amountReg = "([,.\\w]+)";
        String nameReg = "([\\w\\s]+?)";
        String accountReg = "\\([0-9]+\\)";
        String dateReg = "([0-9]{2}/[0-9]{2}/[0-9]{2})";
        String timeReg = "([0-9]{2}:[0-9]{2}:[0-9]{2})";
        String balanceReg = "([,.\\w]+?)";

        String finalReg = "\\( " + headerReg + " " + refReg + " " + amountReg + " sent to " + nameReg + accountReg + " at " + dateReg + " " + timeReg + ", Your Balance is " + balanceReg + ". \\)";

        Pattern pattern = Pattern.compile(finalReg);
        Matcher matcher = pattern.matcher(data);

        if (matcher.find()) {
            MatchResult result = matcher.toMatchResult();
            int groups = result.groupCount();
            for (int i = 0; i < groups; i++) {
                System.out.println(result.group(i + 1));
            }
        }
    }

使用此方法，我们可以从您的输入字符串中找到相关数据。

Answer 2

如果消息语法始终相同，则可以使用一些复杂的拆分字符串，如下所示：

    String msg = "( [-ZAAD SHILLING-] Ref:1141125019 SLSH4,000 sent to AXMED XASAN WARSAME(634458520) at 12/05/19 22:33:03, Your Balance is SLSH44,222.62. )";
    String ref = msg.split("Ref:")[1].split(" ")[0];
    String amount = msg.split("Ref:")[1].split(" ")[1].split(" ")[0];
    String recipient = msg.split("Ref:")[1].split("sent to ")[1].split("\\(")[0];
    String phone = msg.split("Ref:")[1].split("sent to ")[1].split("\\(")[1].split("\\)")[0];
    String date = msg.split("Ref:")[1].split("sent to ")[1].split("\\(")[1].split(" at ")[1].split(" ")[0];
    String time = msg.split("Ref:")[1].split("sent to ")[1].split("\\(")[1].split(" at ")[1].split(" ")[1].split(",")[0];
    String balance = msg.split("Your Balance is ")[1].split("\\)")[0];

    System.out.println("ref: "+ref);
    System.out.println("amount: "+amount);
    System.out.println("recipient: "+recipient);
    System.out.println("phone: "+phone);
    System.out.println("date: "+date);
    System.out.println("time: "+time);
    System.out.println("balance: "+balance);

结果是：

ref: 1141125019
amount: SLSH4,000
recipient: AXMED XASAN WARSAME
phone: 634458520
date: 12/05/19
time: 22:33:03
balance: SLSH44,222.62.

如何将字符串分成几个部分

2 个答案: