Laravel Datatable addColumn仅返回一条记录的ID

时间:2019-06-25 11:57:51

标签: laravel yajra-datatable

我正在尝试使用Yajra数据表将数据表集成到我的网站中。我能够渲染表格,但是遇到了问题。在我放置删除选项的addColumn字段中,ID仅返回单个记录,而不返回每列的特定ID。

这是我的控制器代码

public function fetchData($manifest_no){
            $hwb_data = DB::table('hwb')
                ->join('manifest_records', 'hwb.id', '=', 'manifest_records.hwb_id')
                ->join('consignees', 'consignees.id', '=', 'hwb.client_id')
                ->where('manifest_records.manifest_no', $manifest_no)
                ->get();

        return Datatables::of($hwb_data)
            ->addIndexColumn()
            ->addColumn('action', function($row){
               $idx = $row->id;
                $btn = "<a href='javascript:void(0)' id='delete' data-id='$idx' class='edit btn btn-danger btn-sm'>$idx</a>";
                return $btn;
            })
            ->rawColumns(['action'])
            ->make(true);
    }

这是Datatable渲染

$(function () {
        let table = $('#tableSample').DataTable({
            processing: true,
            serverSide: true,
            ajax: "{{ url("/fetchData/$manifest_no") }}",
            columns: [
                {data: 'id', name: 'id', 'visible': false},
                {data: 'created_at', name: 'created_at'},
                {data: 'hwb_no', name: 'hwb_no'},
                {data: 's_name', name: 's_name'},
                {data: 'c_name', name: 'c_name'},
                {data: 'destination', name: 'destination'},
                {data: 'dr_no', name: 'dr_no'},
                {data: 'commodity', name: 'commodity'},
                {data: 'actual_weight', name: 'actual_weight'},
                {data: 'tp_cbm', name: 'tp_cbm'},
                {data: 'action', name: 'action', orderable: false, searchable: false},
            ]
        });

        $("#tableReload").delegate('#delete', 'click', function (e) {
            e.preventDefault();
            let id = $(this).data('id');
            console.log(id);
        })
    });

I每当我渲染数据时,我总是遇到这个问题。 “操作”按钮的值始终为2

enter image description here

1 个答案:

答案 0 :(得分:0)

我想您必须像这样使用Render函数,而不是后端函数

还尝试在呈现视图之前转储$row和dd,只是检查$ row是否具有您期望的正确值!

$(function () {
            let table = $('#tableSample').DataTable({
                processing: true,
                serverSide: true,
                ajax: "{{ url("/fetchData/$manifest_no") }}",
                columns: [
                    {data: 'id', name: 'id', 'visible': false},
                    {data: 'created_at', name: 'created_at'},
                    {data: 'hwb_no', name: 'hwb_no'},
                    {data: 's_name', name: 's_name'},
                    {data: 'c_name', name: 'c_name'},
                    {data: 'destination', name: 'destination'},
                    {data: 'dr_no', name: 'dr_no'},
                    {data: 'commodity', name: 'commodity'},
                    {data: 'actual_weight', name: 'actual_weight'},
                    {data: 'tp_cbm', name: 'tp_cbm'},

                    {   data: 'id', 
                        name: 'action',
                        orderable: false,
                        searchable: false,
                        "render": function ( data, type, row, meta ) { 
                            return '<button class="delete btn btn-danger" data-id="'+ data +'"> Delete  </button>'
                        }},
                ]
            });

        });