考虑这种结构......
List<IEnumerable<KeyValuePair<String, String>>>
您如何为以下伪代码编写LINQ查询...
SELECT
/* Count of how many [KeyValuePair] exists in [List] */
FROM
[List]
WHERE
[KeyValuePair].Key == "foo"
AND Int32.Parse([KeyValuePair].Value.Replace(".", "")) > 10
...
更新
上面的查询结果,运行在下面的列表中,应该是6(六)...
var list = new List<IEnumerable<KeyValuePair<String, String>>>
{
new []
{
new KeyValuePair<String, String>("foo", "1.1"),
new KeyValuePair<String, String>("foo", "1.2"),
new KeyValuePair<String, String>("foo", "1.3")
},
new []
{
new KeyValuePair<String, String>("foo", "0.1"),
new KeyValuePair<String, String>("foo", "0.2"),
new KeyValuePair<String, String>("foo", "0.3")
},
new []
{
new KeyValuePair<String, String>("foo", "2.1"),
new KeyValuePair<String, String>("foo", "2.2"),
new KeyValuePair<String, String>("foo", "2.3")
}
};
答案 0 :(得分:0)
我从这里得到6 ......
var result = list.Sum(item=>item.Count(kp=>kp.Key == "foo" && int.Parse(kp.Value.Replace(".",String.Empty))>10));
答案 1 :(得分:0)
var result = list.SelectMany(ary =>aryx).Count(item => item.Key == "Foo" && Int32.Parse(item.Value.Replace(".", "")) > 10);
虽然我猜你正在替换“。”因为你想要摆脱成千上万的分隔符,所以你可能想要: Int32.Parse(item.Value, NumberStyles.AllowThousands, CultureInfo.CurrentCulture)
确保正确设置当前文化。
为了清楚起见,我可能会这样写:
var result = list.SelectMany(ary => ary)
.Where(item => item.Key.Equals("Foo", StringComparison.CurrentCulture))
.Select(item =>
Int32.Parse(item.Value.Replace(".", ""))
.Count(value=> value> 10);
理解语法可能如下所示:
var q = from @array in list
from kvp in array
where kvp.Key.Equals("Foo", StringComparison.CurrentCulture)
select .Parse(item.Value.Replace(".", ""));
var result = q.Count(value => value > 10);