不使用-std = c ++ 11时出现libstdc ++错误

Question

我正在练习简单的链表问题，并编写了一个简单的程序来删除链表中的重复项。当我使用g++进行编译时，出现以下错误：

$ g++ removeDuplicateNode.cpp
$ ./a.out < test
./a.out: /lib64/libstdc++.so.6: version `CXXABI_1.3.9' not found (required by ./a.out)

我尝试使用g++ removeDuplicateNode.cpp -std=c++11，并且代码运行正常。该程序如下所示，有人可以帮助我理解为什么会出现此错误，以及为什么我需要在此处使用 -std=c++11 标志

#include <iostream>
struct Node {
    int data;
    struct Node *next;
    Node(int x)
    {
        data = x;
        next = NULL;
    }
};
void print(Node *root)
{
    Node *temp = root;
    while (temp != NULL) {
        std::cout << temp->data << " ";
        temp = temp->next;
    }
}
Node *removeDuplicates(Node *root);
int main()
{
    // your code goes here
    int T;
    std::cin >> T;
    while (T--) {
        int K;
        std::cin >> K;
        Node *head = NULL;
        Node *temp = head;
        for (int i = 0; i < K; i++) {
            int data;
            std::cin >> data;
            if (head == NULL)
                head = temp = new Node(data);
            else {
                temp->next = new Node(data);
                temp = temp->next;
            }
        }
        Node *result = removeDuplicates(head);
        print(result);
        std::cout << std::endl;
    }
    return 0;
}
/*This is a function problem.You only need to complete the function given below*/
void removeNode(Node *prev, Node *curr)
{
    prev->next = curr->next;
    curr->next = nullptr;
    delete curr;
}

// root: head node
Node *removeDuplicates(Node *root)
{
    Node *tmp = root;
    while (tmp != nullptr) {
        int data = tmp->data;
        if (tmp->next != nullptr) {
            int nextData = tmp->next->data;
            if (data == nextData) {
                removeNode(tmp, tmp->next);
                continue;
            }
        }
        tmp = tmp->next;
    }
    return root;
}