Question

我正在尝试创建一个像The Tower的游戏，我有一个基础（基础）和一个移动的图块（从-x到+ x），其大小等于该基数。在点击时，将移除活动磁贴，如果活动磁贴的一部分超出了底座的宽度，则该部分将被破坏，并使用新的尺寸和位置创建一个新的磁贴。当我放置第二块活动瓷砖时，其位置和大小与预期的不同。

    // tile corner sides values
    let left_tile_corner = moving_tile_pos - moving_tile_size * 0.5
    let right_tile_corner = moving_tile_pos + moving_tile_size * 0.5

    // base corner sides values
    let left_base_corner = stationary_tile_pos - stationary_tile_size * 0.5
    let right_base_corner = stationary_tile_pos + stationary_tile_size * 0.5

    if left_tile_corner <= left_base_corner && right_tile_corner > left_base_corner

如果以上条件为真，则应调用以下代码

    var placed_tile_size : CGSize  = CGSize.zero
    var placed_tile_pos  : CGPoint = CGPoint.zero

    var destroyed_tile_size : CGSize  = CGSize.zero
    var destroyed_tile_pos  : CGPoint = CGPoint.zero

    if tiles_placed.isEmpty
    {
        //find the closest point to the center of the previous tile
        let start_pos = moving_tile.position.x + moving_tile.size.width * 0.5

        // new tiles size
        placed_tile_size = CGSize(width: base.size.width * 0.5 + start_pos, height: moving_tile.size.height)
        destroyed_tile_size = CGSize(width: moving_tile.size.width - placed_tile_size.width, height: moving_tile.size.height)

        // new tiles position
        placed_tile_pos = CGPoint(x: -(base.size.width * 0.5 - start_pos) * 0.5, y: moving_tile.position.y)

        let new_dt_pos = placed_tile_pos.x - start_pos
        destroyed_tile_pos = CGPoint(x: moving_tile.position.x + new_dt_pos, y: moving_tile.position.y)

    }
    else
    {
        //find the closest point to the center of the previous tile
        let start_pos = moving_tile.position.x + moving_tile.size.width * 0.5

        // new tiles size
        placed_tile_size = CGSize(width: tiles_placed.last!.size.width * 0.5 + start_pos, height: moving_tile.size.height)
        destroyed_tile_size = CGSize(width: moving_tile.size.width - placed_tile_size.width, height: moving_tile.size.height)

        // new tiles position
        placed_tile_pos = CGPoint(x: -(tiles_placed.last!.size.width * 0.5 - start_pos) * 0.5, y: moving_tile.position.y)

        let new_dt_pos = placed_tile_pos.x - start_pos
        destroyed_tile_pos = CGPoint(x: moving_tile.position.x + new_dt_pos, y: moving_tile.position.y)

    }

    // tower placed tile
    let placed_tile : SKSpriteNode = SKSpriteNode()

    placed_tile.texture = SKTexture(imageNamed: "tile_full_1")
    placed_tile.size = placed_tile_size
    placed_tile.position = placed_tile_pos
    placed_tile.alpha = 1.0
    placed_tile.zPosition = 1
    background.addChild(placed_tile)

    // add a new tile to this vector
    tiles_placed.append(placed_tile)

    // tower destroyed tile
    let destroyed_tile : SKSpriteNode = SKSpriteNode()

    destroyed_tile.texture = SKTexture(imageNamed: "tile_full_2")
    destroyed_tile.size = destroyed_tile_size
    destroyed_tile.position = destroyed_tile_pos
    destroyed_tile.alpha = 1.0
    destroyed_tile.zPosition = 1
    background.addChild(destroyed_tile)

这是游戏的屏幕截图，黄色的方块被放置了，绿色的方块被破坏了。 https://imgur.com/bxltp31

如何在获取前一个图块的大小，位置的同时将多个spritenode放在另一个之上

0 个答案: