Question

我质疑orWhereIn是否使whereNotIn无效，但我没有得到想要的结果！这两个栏目是不同的。

当我更改这些查询项的顺序时，有时只重复最后一行，有时是最后3行，有时结果超出预期

$userposts = userPost::with([
    //RELATIONS--------------------------------------------------------------------------
    'getUser.userbaseinfo',
    'getUser.usercertinfo',
    'getUser.getJobexp',
    'getLike'                           => function ($q) {
        $q->where('liked', 1);
        $q->orderByRaw("FIELD(user_id ," . auth()->user()->id . ") DESC");
    },
    'getLike.getUser.Userbaseinfo',
    'getLike.usercertinfo.getmajor',
    'getLike.usercertinfo.getuniversity',
    'getLike.userjobexp.getCompany',
    'getLike.getcandidate',
    'getLike.userbaseinfo',
    'gettags',
    'getCandidate.getBaseinfo',
    'getCandidate.getCertificate.getmajor',
    'getCandidate.getCertificate.getuniversity',
    'getCandidate.candidjobexp.getCompany',
    'getComments'                       => function ($q) {
        $q->orderByRaw("FIELD(user_id ," . auth()->user()->id . ") DESC");
    },
    'getComments.userbaseinfo',
    'getComments.getcandidate',
    'getComments.usercertinfo.getmajor',
    'getComments.usercertinfo.getuniversity',
    'getComments.userjobexp.getCompany',
    'getfriendreq'                      => function ($q) {
        $q->where('requester_id', auth()->user()->id);
    },
    'getfollow'                         => function ($q) {
        $q->where('req_id', auth()->user()->id);
    },
    'getComments.getLike'               => function ($q) {
        $q->orderByRaw("FIELD(user_id ," . auth()->user()->id . ") DESC");
        $q->where('liked', 1);
    },
    'getComments.getLike.getcandidate',
    'getComments.getLike.getuser',
    'getComments.getLike.Userbaseinfo',
    'getComments.getLike.usercertinfo',
    'getComments.getLike.Userjobexp'    => function ($q) {
        $q->limit(1);
    },
    'getsharedpost.getUser.userbaseinfo',
    'getsharedpost.getUser.usercertinfo',
    'getsharedpost.getUser.getJobexp',
    'getsharedpost.getCandidate',
    'getComments.childcomments'         => function ($q) {
        $q->orderByRaw("FIELD(user_id ," . auth()->user()->id . ") DESC");
    },
    'getComments.childcomments.userjobexp',
    'getComments.childcomments.getcandidate',
    'getComments.childcomments.usercertinfo',
    'getComments.childcomments.userbaseinfo',
    'getComments.childcomments.getLike' => function ($q) {
        $q->orderByRaw("FIELD(user_id ," . auth()->user()->id . ") DESC");
        $q->where('liked', 1);
    },
    'getComments.childcomments.getLike.getuser',
    'getComments.childcomments.getLike.userjobexp',
    'getComments.childcomments.getLike.getcandidate',
    'getComments.childcomments.getLike.usercertinfo',
    'getComments.childcomments.getLike.userbaseinfo'])
    //END OF RELATION----------------------------------------------------------------

    //If I change these query piece order the result might be changed
    ->whereHas('gettags', function ($q) use ($TagsToLook) {
        $q->whereIn('tag_id', $TagsToLook);
    });

$userposts = $userposts->orWhereIn('user_id', $Sourceloader)->where('user_id', auth()->user()->id);

if (count($lastpostid) > 0) {
    $userposts = $userposts->whereNotIn('post_id', $lastpostid);
}

$result = $userposts->orderBy('created_at', 'desc')->limit(3)->get();

所需结果：显示具有尚未显示的关系的帖子Where不是登录用户orWhere user_id等于$ sourceloader。

实际结果：如果whereNotIn（$ lastpostid）中的帖子来自其ID在$ sourceloader中的用户，则whereNotIn不会生效，并且将继续显示以前的帖子。 / p>

Answer 1

只要tag_id在给定集中，或者user_id在给定集中，无论哪种情况，似乎都希望获取结果。没有给定的集合。在这种情况下，您需要对post_id和tag_id条件进行分组。

user_id

这等效于在原始SQL中将它们放在括号中。您可以在“关系后的束缚或子句中”下了解此here。

Laravel`orWhereIn`使`whereNotIn`不生效

1 个答案: