Question

我正在尝试创建某种交叉表查询，以总结我们的人口统计种族数据如何存在。该表的结构包含5个种族列（种族1，种族2，种族3，种族4，种族5）。目的是显示有多少个人适合不同的群体，例如，某个在AS的任何领域中都有价值的人，他们还属于哪些其他（如果有）群体。

这是表格的基本结构

Person_ID   Race1   Race2   Race3   Race4   Race5
815543      WH      BA      IN      UN      UN
815861      WH      HP      AS      UN      UN
823438      WH      BA      IN      UN      UN
825103      WH      BA      AS      UN      UN
825202      BA      WH      IN      UN      UN
825744      IN      WH      BA      UN      UN

这是预期最终结果的示例

        AS      BA      HP      IN      UN      WH
AS      1223    354     165     61      32216   1950
BA      823     112     264     731     119639  6135
HP      96      61      107     63      25510   285
IN      150     555     36      1000    63014   1510
UN      160     499     95      72      179927  3893
WH      2617    6012    477     1647    667126  125000

我想我应该首先取消数据显示，这样我每场比赛都有一个记录，但是我不确定下一步该怎么做。

Answer 1

如果我对您的理解正确，那么当您有固定数量的比赛时，这是一个非常简单的计算。

此查询将返回您正在查找的内容：

declare @RACES TABLE (RACE varchar(16))
insert into @RACES (RACE) values ('AS'), ('BA'), ('HP'), ('IN'), ('UN'), ('WH')

select RACE,
       (select count(*) 
        from MYTABLE
        where RACE in (Race1, Race2, Race3, Race4, Race5) and 
              'AS' in (Race1, Race2, Race3, Race4, Race5)) as 'AS',
       (select count(*) 
        from MYTABLE
        where RACE in (Race1, Race2, Race3, Race4, Race5) and 
              'BA' in (Race1, Race2, Race3, Race4, Race5)) as 'BA',
       (select count(*) 
        from MYTABLE
        where RACE in (Race1, Race2, Race3, Race4, Race5) and 
              'HP' in (Race1, Race2, Race3, Race4, Race5)) as 'HP',
       (select count(*) 
        from MYTABLE
        where RACE in (Race1, Race2, Race3, Race4, Race5) and 
              'IN' in (Race1, Race2, Race3, Race4, Race5)) as 'IN',
       (select count(*) 
        from MYTABLE
        where RACE in (Race1, Race2, Race3, Race4, Race5) and 
              'UN' in (Race1, Race2, Race3, Race4, Race5)) as 'UN',
       (select count(*) 
        from MYTABLE
        where RACE in (Race1, Race2, Race3, Race4, Race5) and 
              'WH' in (Race1, Race2, Race3, Race4, Race5)) as 'WH'
from @RACES

尽管种族数可变，但是您将需要动态构建此SQL语句并使用sp_executesql启动它

https://www.mssqltips.com/sqlservertip/1160/execute-dynamic-sql-commands-in-sql-server/

创建交叉表查询

1 个答案: