获得带有刮擦飞溅的响应主体

Question

我正在使用scrapy 1.6和splash 3.2，我有：

import scrapy
import random
from scrapy_splash import SplashRequest
from scrapy.utils.response import open_in_browser
from scrapy.linkextractors import LinkExtractor

USER_AGENT = 'Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:48.0) Gecko/20100101 Firefox/48.0'

class MySpider(scrapy.Spider):


    start_urls = ["http://yahoo.com"]
    name = 'mytest'

    def start_requests(self):
        for url in self.start_urls:
            yield SplashRequest(url, self.parse, endpoint='render.html', args={'wait': 2.5},headers={'User-Agent': USER_AGENT,'Accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8'})

    def parse(self, response):
        # response.body is a result of render.html call; it
        # contains HTML processed by a browser.
        # from scrapy.http.response.html import HtmlResponse
        # ht = HtmlResponse('jj')
        # ht.body.replace =response
        open_in_browser(response)
        return None

问题是，当我尝试在浏览器中打开响应时，却在记事本中打开了它。

看着https://splash.readthedocs.io/en/stable/scripting-response-object.html。如何激活response.body，以便可以在浏览器中打开响应（我希望能够使用浏览器开发工具来获取xpath）？

Answer 1

open_in_browser()无法将来自Splash的响应检测为HTML响应。这是因为Splash HTML响应对象是Scrapy的TextResponse的子类，而不是HtmlResponse（for now）的子类。

您可以暂时以适合您的用例的方式重新实现open_in_browser()。

Answer 2

我可以和它一起使用

def parse(self, response):
    # response.body is a result of render.html call; it
    # contains HTML processed by a browser.
    from scrapy.http.response.html import HtmlResponse
    ht = HtmlResponse(url=response.url, body=response.body, encoding="utf-8", request=response.request)
    open_in_browser(response)
    return None