Question

Spotify命令

我尝试了很多事情，但我无法使它正常工作

@client.command()
async def spotify(ctx, user: discord.Member = None):
        embedspotify = discord.Embed(title=f"{user.name}'s Spotify", color=0x1eba10)
        embedspotify.add_field(name="Song", value=Spotify.title)
        embedspotify.add_field(name="Artist", value=Spotify.artist)
        embedspotify.add_field(name="Album", value=Spotify.album)
        embedspotify.set_thumbnail(url=Spotify.album_cover_url)

我正在尝试获取歌曲的标题，歌手姓名和我使用命令的人的专辑名称（当他们在听Spotify时）

Answer 1

您需要从Member正在执行的活动列表中获取Spotify实例：

@client.command()
@commands.guild_only() # We can only access activities from a guild
async def spotify(ctx, user: discord.Member = None):
    user = user or ctx.author  # default to the caller
    spot = next((activity for activity in user.activities if isinstance(activity, discord.Spotify)), None)
    if spot is None:
        await ctx.send(f"{user.name} is not listening to Spotify")
        return
    embedspotify = discord.Embed(title=f"{user.name}'s Spotify", color=0x1eba10)
    embedspotify.add_field(name="Song", value=spot.title)
    embedspotify.add_field(name="Artist", value=spot.artist)
    embedspotify.add_field(name="Album", value=spot.album)
    embedspotify.set_thumbnail(url=spot.album_cover_url)
    await ctx.send(embed=embedspotify)

Answer 2

命令效果很好，我决定通过track_id

添加跟踪链接的嵌入

[{spot.title}](https://open.spotify.com/track/{spot.track_id})

async def spotify(self, ctx, user: discord.Member = None):
    user = user or ctx.author  
    spot = next((activity for activity in user.activities if isinstance(activity, discord.Spotify)), None)
    if spot is None:
        await ctx.send(f"{user.name} is not listening to Spotify")
        return
    embed = discord.Embed(title=f"{user.name}'s Spotify", color=spot.color)
    embed.add_field(name="Song", value=spot.title)
    embed.add_field(name="Artist", value=spot.artist)
    embed.add_field(name="Album", value=spot.album)
    embed.add_field(name="Track Link", value=f"[{spot.title}](https://open.spotify.com/track/{spot.track_id})")
    embed.set_thumbnail(url=spot.album_cover_url)
    await ctx.send(embed=embed)
        print(f'{user.name} in {ctx.guild} called the command !spotify')```

如何发出Spotify命令？

2 个答案: