我尝试在<ItemDescription>ZIL PLAY A-</ItemDescription>
<ItemCodeGTIN14>00000000000083</ItemCodeGTIN14> <Quantity>1.00</Quantity> @ <ItemAmount>7.68</ItemAmount>
<Identifier>10</Identifier> (<DiscountPercent>20.0 %</DiscountPercent>) OFF <ItemCodeGTIN14>00000000000083</ItemCodeGTIN14> <DiscountAmount>1.54</DiscountAmount>-
<Identifier>25</Identifier> (<DiscountPercent>5 %</DiscountPercent>) OFF <ItemCodeGTIN14>00000000000083</ItemCodeGTIN14> <DiscountAmount>.31</DiscountAmount>-
上创建循环以及在最终输出<?xml version="1.0"?>
<xsl:stylesheet xmlns="http://www.omnicogroup.com/FPF/namespace"
xmlns:ns1="http://www.omnicogroup.com/FPF/namespace"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml"/>
<xsl:template match="/">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<meta name="viewport" content="width=device-width, initial-scale=1.0" />
</head>
<body>
<table>
<tr>
<xsl:for-each-group select="*" group-starting-
with="MerchandiseItem">
<b>Here is a MerchItem</b><br/> <!--Should repeat (16 times as there are 16 total MerchandiseItem elements in my XML payload. Currently -nothing is displayed and it does not appear that this for-each group is being entered at runtime)-->
</xsl:for-each-group>
</tr>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
上循环
return name.capitalize()假设我选择的名称长度为4，标准设置为（元音，辅音，元音，元音）。而不只是一个名称，我希望输出显示20个选项。
我目前只有一个选择。
答案 0 :(得分：1)
您只要求一次模式并生成尽可能多的名称。我删除了self引用，并将名称longengt替换为函数的参数：
import string
import random
def name_gen(amount, name_len):
"""Generate 'amount' names of 'name_len' specified by the same pattern."""
vowels = 'aeiou'
consonants = [con for con in string.ascii_lowercase if con not in vowels]
pattern = []
for i in range(name_len):
choice = input(f"Select {name_len} letter types of your Baby's name 'v' for Vowel, 'c' for consonant or 'l' for any letter. ENTER LETTER TYPE {i+1}: ").lower()
pattern.append(choice)
def genName(pattern):
"""Generate a name from a pattern-input of v,c,l. Return capitalized."""
n = []
for c in pattern:
if c == 'v':
n.append(random.choice(vowels))
elif c == 'c':
n.append(random.choice(consonants))
else:
n.append(random.choice(string.ascii_letters))
return ''.join(n).capitalize()
return [genName(pattern) for _ in range(amount)]
# print the decomposed list on single lines
print( *name_gen(10,4), sep="\n" )
输出：
# input pattern: vcll
Izow
Iggm
Uqua
Iqtt
Eknt
Ures # only one I would consider a "real" name
Iwny
Epct
Axbm
向字符串中递增添加速度很慢-较短的字符串将被丢弃，而较长的字符串将被创建（字符串是不可变的）-使用字符列表并 join 。