Question

我的这段代码可以正常工作，但是会在代码行之后剪切消息：

message=Sprintf("<p>Dear user,<br />
Your request have been initiated from your Account. Enter your code <br /><br />
Your Code is: %u", $data['code'], 
================================================Doesn't send this part below
"Your Code will expire in 30 minutes, 
Thank you for choosing Industrial Bank, we are determined to making life better for you.<br />
<br /><br />
Regards,<br />
Apptix<br />
")

我尝试用有问题的部分创建另一个变量。

message=Sprintf("<p>Dear user,<br />
Your  transfer request have been initiated from your Private Account. Enter your code <br /><br />
Your Code is: %u", $data['code'] <br /> <br /> 
"Your Code will expire in 30 minutes, 
Thank you for choosing Industrial Bank, we are determined to making life better for you.<br />
<br /><br />
Regards,<br />
Apptix<br />
")

Answer 1

sprintf（）的第一个参数是字符串模板。您正在尝试使用两个单独的模板，这些模板将不起作用。你有：

sprintf('template 1', $data['code'], 'template 2');

您要

sprintf('template 1 template 2', $data['code']);

或者也许：

sprintf('template 1', $data['code']) . 'template2';

Answer 2

使用美元符号初始化变量
使用sprintf函数而不是Sprintf
使用％s代替％

u之后不需要逗号 $ data

$mesage = sprintf("<p>Dear user,<br />
Your request have been initiated from your Account. Enter your code <br /><br />
Your Code is: %s", $data['code']);
// output  $message
echo $mesage;

之后，$ message变量将使用$ data ['code']内容代替％s

有没有办法解决这个Sprintf问题

2 个答案: