Question

我无法使用以下（测试）代码。这使我在此行出现“参数计数不匹配”错误

dataTable.Merge(CreateDataTableFromObject(info.GetValue(inputObject)));

整个代码如下：

public object SerializeThis(DataTable dataTable1, DataTable dataTable2)
        {
        string jsonString = @"{'EquipmentNumber':'CP5301078','Data_General_Exp': {'Authgrp':'CP01','Objecttype':'9A1B'}}";

            var jConvertObejct = (JsonConvertObject)JsonConvert.DeserializeObject(jsonString, typeof(JsonConvertObject));
            var jObject = JObject.Parse(jsonString);

            dataTable1 = CreateDataTableFromObject(jConvertObejct);
            dataTable2 = CreateDataTableFromObject(jObject);

            return jConvertObejct;
        }

public DataTable CreateDataTableFromObject(object inputObject)
        {
            DataTable dataTable = new DataTable();
                Type type = inputObject.GetType();
                var properties = type.GetProperties();
                PropertyInfo info;

                for (int i = 0; i < properties.Length; i++)
                {
                    info = properties[i];
                    if (info.GetValue(inputObject).GetType().GetProperties().Count() > 2)
                        dataTable.Merge(CreateDataTableFromObject(info.GetValue(inputObject)));
                    else
                        if (!dataTable.Columns.Contains(info.Name))
                        dataTable.Columns.Add(new DataColumn(info.Name, Nullable.GetUnderlyingType(info.PropertyType) ?? info.PropertyType));
                }
            return dataTable;
        }

请注意，我正在尝试对JsonConvert对象和JObject做相同的事情-执行

时出现错误

CreateDataTableFromObject(object inputObject)

在JObject对象上，而不在JsonConvert对象上。

我需要一个JObject解决方案，因为我必须处理一些未知的json字符串，我需要将其放入DataTable中（列名是属性名，行值是json对象的值）。我已经省略了用法。我看不到任何其他stackoverflow文章都回答了这个问题。

Answer 1

好的-我发现我有点纠结了。并得出以下解决方案：

module.exports{install}

现在只有一个问题，是否可以重新编写，以便

        public static DataTable DeSerializeThis(string jsString)
        {
            const string json1 = @"{""EquipmentNumber"":""CP1"",""Authgrp"":""CP01"",""Objecttype"":""9A1A""}";
            const string json2 = @"{""EquipmentNumber"":""CP2"",""Authgrp"":""CP02"",""Objecttype"":""9B1B""}";
            List<JObject> list = new List<JObject>();
            list.Add(JObject.Parse(json1));
            list.Add(JObject.Parse(json2));
            DataTable table = ToDataTable(list);
            return table;
        }
        static public DataTable ToDataTable(List<JObject> list)
        {
            DataTable dataTable = new DataTable();
            int i = 0;
            foreach (JToken content in list.ToList<JToken>())
            {
                dataTable.Rows.Add();
                foreach (JProperty prop in content)
                {
                    if (i == 0)
                    {
                        dataTable.Columns.Add(prop.Name);
                    }
                    dataTable.Rows[i][prop.Name] = prop.Value;
                }
                i++;
            }
            return dataTable;
        }

可以是

ToDataTable(List<JObject> list)

相反-我还没有找到答案...

将jObject.Parse和JsonConvert.DeserializeObject数据转换为DataTable，导致参数计数不匹配异常

1 个答案: