Question

String fullname="Mr Vivek N Nandakumar Sr";
String [] strst={"Sr.", "sr.", "Jr.", "jr.","Jr ","jr ","Sr ","sr "," Jr"," jr"," Sr"," sr",",I",".I","I.","II","III"," IV","IV ",".IV",",IV", "V.","V ",".V",",V","VI", "VII", "VIII", "IX", "X" ,"M.D","MBA","PhD","M.A","Mr.","Mr ","Mrs.","Miss","MISS","miss","MR ","MRS ","mr ","mrs "," mr"," mrs","Dr ","DR ","Dr.","DR.",")","("};

我只想从全名中删除此给定的数组字符串。

我希望输出像....“ Vivek N Nandakumar”

Answer 1

我不知道您使用的Java是什么版本，但是在Java 8中，我将使用类似这样的流：

Arrays.stream(fullname.split(" ")).filter(namePart -> Arrays.stream(strst).noneMatch(str -> str.trim().equals(namePart))).collect(Collectors.joining(" "));

对我来说，输出就如您所愿。

EDIT

JAVA 7就是这种情况。在此之前，您必须实现自己的搜索。

    String fullname="Mr Vivek N Nandakumar Sr";
    String [] strst={"Sr.", "sr.", "Jr.", "jr.","Jr ","jr ","Sr ","sr "," Jr"," jr"," Sr"," sr",",I",".I","I.","II","III"," IV","IV ",".IV",",IV", "V.","V ",".V",",V","VI", "VII", "VIII", "IX", "X" ,"M.D","MBA","PhD","M.A","Mr.","Mr ","Mrs.","Miss","MISS","miss","MR ","MRS ","mr ","mrs "," mr"," mrs","Dr ","DR ","Dr.","DR.",")","("};
    Arrays.sort(strst);
    StringBuilder sb = new StringBuilder();

    for (String namePart :
            fullname.split(" ")) {
        if (Arrays.binarySearch(strst, namePart, new Comparator<String>() {
            @Override
            public int compare(String o1, String o2) {
                return o1.trim().compareTo(o2.trim());
            }
        }) < 0 ) {
            sb.append(namePart).append(" ");
        }
    } 
    return sb.toString();

Answer 2

如果您对空间复杂度没有限制，则尝试在数组中使用空格（如果用空格分隔）来分割主字符串，并检查给定数组中的每个值（如果找到）从主字符串数组中删除该值最后连接主字符串数组。我会说使用set存储第二个列表，它将帮助您提高时间性能。它将把时间从O（n ^ 2）减少到O（n）。

删除给定字符串中的数组字符串？

2 个答案: