使用先前定义的类的PHP-DI

时间:2019-06-24 08:21:29

标签: php php-di

我正在尝试改善我的PHP-DI配置,现在我卡住了。

我想将已经定义的类重用于另一个类。

entityManager类应来自Database->getEntityManager

这是我的di配置文件的一部分:

return [
    'database.user'     => 'xxxxxxx',
    'database.password' => 'xxxxxxx',
    'database.name'     => 'xxxxxxx',
    'database.host'     => '127.0.0.1',
    'database.port'     => 3306,

    \ABCData\Database\Database::class => DI\autowire()->constructor(
        DI\get('database.user'),
        DI\get('database.password'),
        DI\get('database.name'),
        DI\get('database.host'),
        DI\get('database.port')
    ),


//    \Doctrine\ORM\EntityManager::class => DI\factory(function () {
//        $database = new ABCData\Database\Database(
//            \ABCData\Database\Config::DB_USER,
//            \ABCData\Database\Config::DB_PASSWORD,
//            \ABCData\Database\Config::DB_DATABASE,
//            \ABCData\Database\Config::DB_HOST
//        );
//        return $database->getEntityManager();
//    }),


    \Doctrine\ORM\EntityManager::class => DI\autowire(\ABCData\Database\Database::class)->method('getEntityManager'),
...

当我注入数据库时​​,这很好。注释过的定义很好用,但我想达到的是最后一行,但失败了。

这是我对数据库类的完整实现:​​

private $userName;

private $password;

private $database;

private $host;

private $port;

public function __construct($username, $password, $database, $host, $port = 3306)
{
    $this->userName = $username;
    $this->password = $password;
    $this->database = $database;
    $this->host = $host;
    $this->port = $port;
}

public function getEntityManager()
{
    $isDevMode = true;
    $paths = [APP_DIR . 'classes/Entities'];
    $connectionCredentials = $this->getConnectionCredentials();

    $config = Setup::createAnnotationMetadataConfiguration($paths, $isDevMode);
    $entityManager = \Doctrine\ORM\EntityManager::create($connectionCredentials, $config);
    $connection = $entityManager->getConnection();

    $sqlSchemaManager = new SQLServerSchemaManager($connection);
    $sqlSchemaManager->getDatabasePlatform()->registerDoctrineTypeMapping('enum', 'string');

    return $entityManager;
}

private function getConnectionCredentials()
{
    return [
        'driver'   => 'pdo_mysql',
        'user'     => $this->userName,
        'password' => $this->password,
        'dbname'   => $this->database,
        'host'     => $this->host,
        'port'     => $this->port
    ];
}

当我的代码需要实例化entityManager时,出现此错误:

Entry "ABCData\ABCDataAPI\CronJob" cannot be resolved: Entry "ABCData\DataStructure\Save" cannot be resolved: Entry "Doctrine\ORM\EntityManager" cannot be resolved: Parameter $username of __construct() has no value defined or guessable
Full definition:
Object (
    class = ABCData\Database\Database
    lazy = false
    __construct(
        $username = #UNDEFINED#
        $password = #UNDEFINED#
        $database = #UNDEFINED#
        $host = #UNDEFINED#
        $port = (default value) 3306
    )
    getEntityManager(

    )
)

似乎没有使用先前定义的数据库对象。

我怎么了?

1 个答案:

答案 0 :(得分:0)

好的,我误解了文档。

这就是我所做的。如果您有更好的主意,请告诉我:

\Doctrine\ORM\EntityManager::class => DI\factory(function (\ABCData\Database\Database $database) {
    return $database->getEntityManager();
}),