Question

我要加载具有company_id = 28的用户。我放了where子句，但它不起作用，集合返回了所有记录。

MyController.php

public function index($type, $company_id = '')
{
    $user = User::whereHas('roles', function ($query) use ($type) {
        $query->where('name', '=', $type);
    })->get();

    $users = $user->load(['userSetting' => function ($query) {
        $query->where('company_id', '28');
    }]);

    return response()->json($users);
}

User.php

public function userSetting()
{
   return $this->hasOne('App\UserSettings', 'user_id');
}

Answer 1

您可以使用filter：

filter方法使用给定的回调过滤集合，仅保留那些通过给定的真相测试的项。

例如：

$collection = collect([1, 2, 3, 4]);
$filtered = $collection->filter(function ($value, $key) {
    return $value > 2;
});
$filtered->all(); // [3, 4]

在您的控制器内：

public function index($type, $company_id = '')
{
    $users = User::whereHas('roles', function ($query) use ($type) {
        $query->where('name', '=', $type);
    })->get();

    //If you want to load the relationship with the users:
    /*
    $users = User::whereHas('roles', function($query) use ($type) {
        $query->where('name', '=', $type)
    })
        ->with('userSettings')
        ->get()
    */

    $users = $users->filter($user){
        return $user->userSettings->company_id == 28;
    }

    return response()->json($users);
}

希望有帮助。

laravel渴望与where子句不起作用的加载关系

1 个答案: