django复制迁移表的模型名称

时间:2019-06-23 11:37:54

标签: python django migration

当我迁移django 2模型时,它制作的表没有任何问题,但是表的名称是这样的:‌nameofmodel_nameofmodel !!!例如,booking_booking !!! 这是我的代码:

    from django.db import models


# Create your models here.
class Booking(models.Model):
    user_id = models.CharField(max_length=50, null=True )
    operator_id = models.CharField(max_length=50, null=True )
    computed_net_price = models.CharField(max_length=50, null=True )
    final_net_price = models.CharField(max_length=50, null=True )
    payable_price = models.CharField(max_length=50, null=True )
    booking_status = models.CharField(max_length=50, null=True )
    guest_name = models.CharField(max_length=50, null=True )
    guest_last_name = models.CharField(max_length=50, null=True )
    guest_cellphone = models.CharField(max_length=50, null=True )
    from_date = models.DateTimeField(max_length=50, null=True )
    to_date = models.DateTimeField(max_length=50, null=True )
    is_removed = models.IntegerField(null=True )

这是我的序列化器:

from rest_framework import serializers
from .models import Booking
class BookingSerializer(serializers.ModelSerializer):
     class Meta:
         model = Booking
         fields =(
             'user_id',
             'computed_net_price',
             'final_net_price',
             'payable_price',
             'booking_status',
             'booking_status',
             'guest_name',
             'guest_last_name',
             'guest_cellphone',
             'guest_cellphone',
             'guest_cellphone',
             'operator_id',
             'is_removed',
         )

那么django的标准命名是什么?如果我想以其他方式使用它,而我做得正确还是不正确

1 个答案:

答案 0 :(得分:1)

您可以这样:

class YourModel(models.Model):
    # first_field = ....
    # second_field = ....

    class Meta:
        db_table = 'table_name'

https://docs.djangoproject.com/en/2.2/topics/db/models/#meta-options