Question

我正在运行一个使用GRPC工具从原始文件生成c＃类的过程。该代码在我的开发计算机上工作正常，但是一旦部署在azure上，该过程就会运行，但会返回ExitCode = -1073740791并且输出为字符串空。

我已经记录了我执行的命令，如果我尝试在Kudu控制台中执行该命令，它将正常工作，并且会按预期生成c＃文件。

命令如下：

Tools\bin\tools\windows_x86\protoc.exe 
-ID:\local\LocalAppData\GrpcTester\0969261f-bfa7-45a8-bba1-7e1ccd3818e7\protos 
--csharp_out=D:\local\LocalAppData\GrpcTester\0969261f-bfa7-45a8-bba1-7e1ccd3818e7\csharpfiles 
--grpc_out=D:\local\LocalAppData\GrpcTester\0969261f-bfa7-45a8-bba1-7e1ccd3818e7\csharpfiles 
--plugin=protoc-gen-grpc="Tools\bin\tools\windows_x86\grpc_csharp_plugin.exe" 
D:\local\LocalAppData\GrpcTester\0969261f-bfa7-45a8-bba1-7e1ccd3818e7\protos\mobile_backend.proto

private bool GenerateGRPCCSharpFiles(TestProject testProject)
        {
            bool succes = false;
            var outputFolder = WorkspaceManager.GetProjectSubFolder(testProject.Id.ToString(), WorkspaceManager.CSharpFilesPath);
            var protoFilesFolder = WorkspaceManager.GetProjectSubFolder(testProject.Id.ToString(), WorkspaceManager.ProtosPath);


            // Install tools
            RequireTools().Wait();

            var protoc = ProtocPath();
            var plugin = ProtocPluginPath();
            logger.LogDebug($"GenerateGRPCCSharpFiles : protoc: {protoc}");
            logger.LogDebug($"GenerateGRPCCSharpFiles : plugin: {plugin}");

            //string protocol = Path.Combine(protoFilesFolder, protoFiles.FirstOrDefault().FileName);
            string protocol = Directory.GetFiles(protoFilesFolder).FirstOrDefault();

            var command = new string[]
            {
                $"-I{protoFilesFolder}",
                $"--csharp_out={outputFolder}",
                $"--grpc_out={outputFolder}",
                $"--plugin=protoc-gen-grpc=\"{plugin}\"",
                protocol,
            };


            try
            {
                using (Process process = new Process())
                {
                    process.StartInfo.UseShellExecute = false;
                    process.StartInfo.FileName = protoc;
                    process.StartInfo.Arguments = string.Join(' ', command);
                    process.StartInfo.CreateNoWindow = true;
                    process.StartInfo.RedirectStandardOutput = true;

                    process.Start();
                    process.WaitForExit();

                    using (var streamReader = new StreamReader(process.StandardOutput.BaseStream))
                    {
                        var response = streamReader.ReadToEnd();
                        logger.LogDebug($"GenerateGRPCCSharpFiles: Completed output: {response.ToString()}");
                    }

                    succes = process.ExitCode == 0;

                };
            }
            catch (Exception ex)
            {
                throw ex;
            }

            return succes;
        }

Answer 1

这与应用服务Sandbox相关。请关注this，以获取更多信息。

Answer 2

它与必须在WaitForExit之前执行的RedirectStandardOutput（愚蠢的错误）有关。查看修改后的代码：

                process.StartInfo.FileName = protoc;
                process.StartInfo.Arguments = string.Join(' ', command);

                //You must set UseShellExecute to false if you want to set RedirectStandardOutput to true.
                //Otherwise, reading from the StandardOutput stream throws an exception.
                process.StartInfo.UseShellExecute = false;
                process.StartInfo.CreateNoWindow = true;

                process.StartInfo.RedirectStandardError = true;
                process.StartInfo.RedirectStandardOutput = true;

                string eOut = null;
                process.ErrorDataReceived += new DataReceivedEventHandler((sender, e) => { eOut += e.Data; });

                process.Start();

                // To avoid deadlocks, always read the output stream first and then wait.
                // To avoid deadlocks, use an asynchronous read operation on at least one of the streams.
                process.BeginErrorReadLine();
                string output = process.StandardOutput.ReadToEnd();
                logger.LogDebug($"GenerateGRPCCSharpFiles: Completed output: {output.ToString()}");

                process.WaitForExit();

从Azure App Service执行流程

2 个答案: