我有3个sqlalchemy模型设置,它们都是一对多的关系。用户模型包含许多任务模型,任务模型包含许多子任务模型。当我执行test_script.py时,出现错误sqlalchemy.orm.exc.UnmappedInstanceError: Class 'builtins.NoneType' is not mapped
。
我已经阅读并尝试了每个模块的一些不同关系。我的目标是能够在用户和任务模型中包含其正确子代的列表。我最终想访问列表项,例如user_x.task[3].subtask[1]
这是代码, (模型,脚本,错误)
模型
class User(Base):
""" User Model for storing user related details """
__tablename__ = 'Users'
id = Column(Integer, primary_key=True, autoincrement=True, nullable=False)
username = Column(String(255), nullable=False)
password_hash = Column(String(128), nullable=False)
email = Column(String(255), nullable=False, unique=True)
created_date = Column(DateTime, default=datetime.utcnow)
tasks = relationship(Task, backref=backref("Users", uselist=False))
def __init__(self, username: str, password_hash: str, email: str):
self.username = username
self.password_hash = password_hash
self.email = email
class Task(Base):
""" Task Model for storing task related details """
__tablename__ = 'Tasks'
id = Column(Integer, primary_key=True, autoincrement=True, nullable=False)
title = Column(String(255), nullable=False)
folder_name = Column(String(255), nullable=True)
due_date = Column(DateTime, nullable=True)
starred = Column(Boolean, default=False)
completed = Column(Boolean, default=False)
note = Column(String, nullable=True)
created_date = Column(DateTime, default=datetime.utcnow)
user_id = Column(Integer, ForeignKey('Users.id'))
subtasks = relationship(Subtask, backref=backref("Tasks", uselist=False))
def __init__(self, title: str, **kwargs):
self.title = title
self.folder_name = kwargs.get('folder_name', None)
self.due_date = kwargs.get('due_date', None)
self.starred = kwargs.get('starred', False)
self.completed = kwargs.get('completed', False)
self.note = kwargs.get('note', None)
class Subtask(Base):
""" Subtask Model for storing subtask related details """
__tablename__ = 'Subtasks'
id = Column(Integer, primary_key=True, nullable=False, autoincrement=True)
title = Column(String(255), nullable=False)
completed = Column(Boolean, default=False)
task_id = Column(Integer, ForeignKey('Tasks.id'))
def __init__(self, title: str, **kwargs):
self.title = title
self.completed = kwargs.get('completed', False)
test_script.py
session1 = create_session()
user1 = User(
username="Stephen",
password_hash="p-hash",
email="stephen@gmail.com"
).tasks.append(
Task(
title='Delete Me',
folder_name='Folder 1'
).subtasks.append(
Subtask(
title='Delete Me 2'
)
)
)
session1.add(user1)
session1.commit()
session1.close()
错误消息
/Users/StephenCollins/Respositories/pycharm_workspace/Personal/BusyAPI_v1/venv/bin/python /Users/StephenCollins/Respositories/pycharm_workspace/Personal/BusyAPI_v1/tests/test_script.py
Traceback (most recent call last):
File "/Users/StephenCollins/Respositories/pycharm_workspace/Personal/BusyAPI_v1/venv/lib/python3.7/site-packages/sqlalchemy/orm/session.py", line 1943, in add
state = attributes.instance_state(instance)
AttributeError: 'NoneType' object has no attribute '_sa_instance_state'
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "/Users/StephenCollins/Respositories/pycharm_workspace/Personal/BusyAPI_v1/tests/test_script.py", line 24, in <module>
session1.add(user1)
File "/Users/StephenCollins/Respositories/pycharm_workspace/Personal/BusyAPI_v1/venv/lib/python3.7/site-packages/sqlalchemy/orm/session.py", line 1945, in add
raise exc.UnmappedInstanceError(instance)
sqlalchemy.orm.exc.UnmappedInstanceError: Class 'builtins.NoneType' is not mapped
希望我已经接近了,但是如果我完全朝错误的方向前进,请告诉我。我在以前的实习中使用过Hibernate,但是我在python,sqlalchemy和mysql中是自学的(最好的一种)。
答案 0 :(得分:1)
在Python中就地改变对象的方法通常返回None
。您分配的表达式链创建了模型对象,访问了一个关系属性,并附加到该属性上,该属性返回None
。拆分操作:
user1 = User(
username="Stephen",
password_hash="p-hash",
email="stephen@gmail.com"
)
task1 = Task(
title='Delete Me',
folder_name='Folder 1'
)
task1.subtasks.append(
Subtask(
title='Delete Me 2'
)
)
user1.tasks.append(task1)
答案 1 :(得分:0)
由于您正在重载__init__
,因此有必要在模型中初始化超类:
class User(Base):
def __init__(self, username: str, password_hash: str, email: str):
// Initialize self
[...]
// Initialize base class
super(User, self).__init__()
请注意,通常不需要定义自己的构造函数__init__
,因为声明性基类已经定义了一个构造函数,该构造函数采用与模型属性相对应的**kwargs
。