Question

我有一个这样的数据集：

FILE_NUMBER, DATE_RECEIVED, FILE_TYPE

FILE_TYPE有大约10个选项。我希望生成一个汇总表，该表显示过去四年（包括今年）中的每一年：

YEAR, TOTAL_RECEIVED_TO_DATE, FILE_TYPE_1_TOTAL, FILE_TYPE_2_TOTAL, ....
2016, 3000, 126, 234, ....
2017, 3200, 123, 242, ....
2018, 3100, 234, 267, ....

我尝试了几个派生表，但没有成功。

Answer 1

您可以使用条件聚合：

select year(DATE_RECEIVED), count(*) as total,
       sum(case when FILE_TYPE = 1 then 1 else 0 end) as file_type_1,
       sum(case when FILE_TYPE = 2 then 1 else 0 end) as file_type_2,
       . . .,
       sum(case when FILE_TYPE = 10 then 1 else 0 end) as file_type_10
from x
group by year(DATE_RECEIVED)

在SQL中，为变量的所有选项创建具有最新小计的年度汇总表

1 个答案: