我需要缩短它，但是我不知道是否有一种方法可以在excel中使用“ for”循环
=IF($B$1=1,COUNT(ABS!AG2),IF($B$1=2,COUNT(ABS!AG2:AH2),IF($B$1=3,COUNT(ABS!AG2:AI2),IF($B$1=4,COUNT(ABS!AG2:AJ2),IF($B$1=5,COUNT(ABS!AG2:AK2),IF($B$1=6,COUNT(ABS!AG2:AL2),IF($B$1=7,COUNT(ABS!AG2:AM2),IF($B$1=8,COUNT(ABS!AG2:AN2),IF($B$1=9,COUNT(ABS!AG2:AO2),IF($B$1=10,COUNT(ABS!AG2:AP2),IF($B$1=11,COUNT(ABS!AG2:AQ2),IF($B$1=12,COUNT(ABS!AG2:AR2),IF($B$1=13,COUNT(ABS!AG2:AS2),IF($B$1=14,COUNT(ABS!AG2:AT2),IF($B$1=15,COUNT(ABS!AG2:AU2),IF($B$1=16,COUNT(ABS!AG2:AV2),IF($B$1=17,COUNT(ABS!AG2:AW2),IF($B$1=18,COUNT(ABS!AG2:AX2),IF($B$1=19,COUNT(ABS!AG2:AY2),IF($B$1=20,COUNT(ABS!AG2:AZ2),IF($B$1=21,COUNT(ABS!AG2:BA2),IF($B$1=22,COUNT(ABS!AG2:BB2),IF($B$1=23,COUNT(ABS!AG2:BC2),IF($B$1=24,COUNT(ABS!AG2:BD2),IF($B$1=25,COUNT(ABS!AG2:BE2),IF($B$1=26,COUNT(ABS!AG2:BF2),IF($B$1=27,COUNT(ABS!AG2:BG2),IF($B$1=28,COUNT(ABS!AG2:BH2),IF($B$1=29,COUNT(ABS!AG2:BI2),IF($B$1=30,COUNT(ABS!AG2:BJ2)*IF($B$1=31,COUNT(ABS!AG2:BK2),0)))))))))))))))))))))))))))))))
答案 0 :(得分：2)
使用INDEX返回范围的结尾：
=IFERROR(COUNT(ABS!AG2:INDEX(ABS!AG2:BK2,$B$1)),0)