Question

我有两个不同的对象，如果第二个对象的至少一个属性与第一个对象匹配，我想返回true。如果不是，则返回false。我已经尝试过.hasOwnProperty和.keys方法，但是无法处理。这是下面的示例代码。谢谢。

let propchecker = (a,b) =>{
    if(/* at least one property matches exact */){
        return true;
     }

    else {
        return false;
    }
}

let origin = {name: "John", surname: "Doe"};

let first = {name: "John", surname: "Roe" };
let second = {name: "Jane", surname: "Doe"};
let third = {name: "Richard", surname: "Roe"};

console.log(propchecker(origin,first)); //Should return True.
console.log(propchecker(origin,second)); //Should return True.
console.log(propchecker(origin,third)); //Should return False.

Answer 1

您可以使用Object.keys()获取一个对象的键，然后在其上使用some()。

let propchecker = (a,b) => Object.keys(a).some(x => a[x] === b[x])

let origin = {name: "John", surname: "Doe"};

let first = {name: "John", surname: "Roe" };
let second = {name: "Jane", surname: "Doe"};
let third = {name: "Richard", surname: "Roe"};

console.log(propchecker(origin,first)); //Should return True.
console.log(propchecker(origin,second)); //Should return True.
console.log(propchecker(origin,third)); //Should return False.

Answer 2

可能有更短的解决方案，但这很好用

let propchecker = (a,b) =>{
for (let key in a) {
  for (let key2 in b ){
    if(a[key] == b[key2]){
     return true
   }
 }
}
return false
}

let origin = {name: "John", surname: "Doe"};

let first = {name: "John", surname: "Roe" };
let second = {name: "Jane", surname: "Doe"};
let third = {name: "Richard", surname: "Roe"};

console.log(propchecker(origin,first)); //Should return True.
console.log(propchecker(origin,second)); //Should return True.
console.log(propchecker(origin,third)); //

Answer 3

尝试一下

let propchecker = (a,b) =>{
   result =  false;
   for(let ele in first){
       result  = result  || (a[ele] === b[ele])
    }
   return result
 }

let origin = {name: "John", surname: "Doe"};

let first = {name: "John", surname: "Roe" };
let second = {name: "Jane", surname: "Doe"};
let third = {name: "Richard", surname: "Roe"};

console.log(propchecker(origin,first)); //Should return True.
console.log(propchecker(origin,second)); //Should return True.
console.log(propchecker(origin,third)); //Should return False.

Answer 4

看起来它已经被回答了，但我也将帽子戴在戒指里。所有这些答案几乎都在做同一件事。

let propchecker = (a,b) =>{
    var check = false;
    Object.keys(a).forEach(function(key) {
        if(a[key] == b[key]) {
            check = true;
        }
    })

    return check;
}

let origin = {name: "John", surname: "Doe"};

let first = {name: "John", surname: "Roe" };
let second = {name: "Jane", surname: "Doe"};
let third = {name: "Richard", surname: "Roe"};

console.log(propchecker(origin,first)); //Should return True.
console.log(propchecker(origin,second)); //Should return True.
console.log(propchecker(origin,third)); //Should return False.

如何检查另一个对象中是否也存在对象属性？

4 个答案: