Question

在执行当前Web请求期间发生未处理的异常。请查看堆栈跟踪，以获取有关错误及其在代码中起源的更多信息。

public class HomeController : Controller
{
    [HttpGet]
    [ActionName("Registration")]
    public ActionResult Registration_Get()
    {
        //Contry();
        return View();
    }

    [HttpPost]
    [ActionName("Registration")]
    public ActionResult Registration_Post()
    {
        Registration register = new Registration();
        TryUpdateModel(register);

        if (ModelState.IsValid)
        {
            AddStudent(register);

            return RedirectToAction("Registration");
        }

        return View(register);
    }

    public ActionResult AddStudent(Registration r)
    {
        OQContext db = new OQContext();
        db.Registrations.Add(r);
        db.SaveChanges();
        return View();
    }

}

我想将表单数据保存到数据库表，但是 db.Registrations.Add（r）上的 AddStudent 操作方法中发生了异常；

Answer 1

将控制器更改为

[HttpGet]
[ActionName("Registration")]
public ActionResult Registration_Get()
{
    //Contry();
    return View();
} 

[HttpPost]
[ActionName("Registration")]
public ActionResult Registration_Post(Registration r)
{
    //This needs to come from the view
    //Registration register = new Registration();
    //TryUpdateModel(r);

    if (ModelState.IsValid)
    {
        AddStudent(r);

        return RedirectToAction("Registration");
    }

    return View(r);
}

您尚未从视图中传递模型

Answer 2

更改这样的控制器方法：

   public ActionResult AddStudent()
   {
        return View();
   }

   [HttpPost]
   public ActionResult AddStudent(Registration r)
   {
     try
     {
      OQContext db = new OQContext();
       db.Registrations.Add(r);
       db.SaveChanges();
     }
     catch(Exception ex)
     {
     }
     return View();
   }

当前Web请求的执行期间发生未处理的异常。无法检查模型兼容性

2 个答案: