Question

我有这段代码，它在0到24之间打印数字，并且在时间等于8、16、24时打印需要休息一下，现在的关键是当时间是8、16和24时打印时间和语句“您需要休息一下8”，但是在迭代代码之后，在时间下方又声明它再次打印时间，请您说明如何避免这种情况？

time=0
while time!=25:
    if time%8==0 and time!=0:
        print (time,'you need to take a break')
    if time == 25:
        time=0
    print (time)
    time+=1

This is the result i get.
0
1
2
3
4
5
6
7
8 you need to take a break
8
9
10
11
12
13
14
15
16 you need to take a break
16
17
18
19
20
21
22
23
24 you need to take a break
24

And this is want i want to get
0
1
2
3
4
5
6
7
8 you need to take a break
9
10
11
12
13
14
15
16 you need to take a break
17
18
19
20
21
22
23
24 you need to take a break

Answer 1

time=0
while time!=25:
    if time%8==0 and time!=0:
        print(time,'you need to take a break')
    else:
        print(time)
    if time == 25:
        time=0
    time+=1

Answer 2

您始终打印time，您必须分支此决定，并且仅当您不打印“请休息一下”时才这样做。

为了更加简洁，您可以随时打印时间，但可以选择后缀（空或“稍作休息”

time=0
while time!=25:
    print(time,'you need to take a break' if time%8==0 and time!=0 else '')
    if time == 25:
        time=0
    time+=1

Answer 3

可以使用一个相同的衬纸，如下所示：

print(*["{} you need to take a break".format(time) if time%8==0 and time!=0 else time for time in range(25)], sep="\n")

仅供参考：如果您确定迭代次数，请使用for循环！

Answer 4

在第一个if语句中使用else，并在else语句中使用打印时间，这将为您提供所需的输出。

time=0
while time!=25:
    if time%8==0 and time!=0:
         print (time,'you need to take a break')
    else:
         print(time)
    if time == 25:
         time=0
#        print (time)
    time+=1

如何避免两次迭代，并将语句打印两次

4 个答案: