运行Python代码时出现回溯错误

时间:2019-06-21 12:45:53

标签: python-3.x

在Jupyter Notebook中运行Python代码时,出现回溯错误,我不确定是什么原因导致了回溯错误。任何帮助将不胜感激。

import pandas as pd
import requests
import target
import pip_api
from bs4 import BeautifulSoup

res = requests.get("http://web.archive.org/web/20070826230746/http://www.bbmf.co.uk/july07.html")
soup = BeautifulSoup(res.content,'lxml')
table = soup.find_all('table')[0]

df = pd.read_html(str(table))
df = df[1]
df = df.rename(columns=df.iloc[0])
df = df.iloc[2:]
df.head(15)

Southport = df[
    (
        df['Location'].str.contains('- Display') & 
        df['Lancaster'] == '' & 
        df['Dakota'] == 'D' & 
        df['Spitfire'] == 'S' & 
        df['Hurricane'] == 'H'
    )
] | df[
    (
        df['Location'].str.contains('- Display') & 
        df['Lancaster'] == '' & 
        df['Dakota'] == 'D' & 
        df['Spitfire'] == 'S' &
        df['Hurricane'] == ''
    )
] | df[
    (
        df['Location'].str.contains('- Display') & 
        df['Lancaster'] == '' & 
        df['Dakota'] == 'D' & 
        df['Spitfire'] == 'SS' &
        df['Hurricane'] == ''
    )
]

这是回溯错误的一部分,有什么想法吗? :-

TypeError Traceback (most recent call last)
    <ipython-input-1-5ec7c798b521> in <module>
         38             df['Hurricane'] == ''
         39         )
    ---> 40     ] | df[
         41         (
         42             df['Location'].str.contains('- Display') &

    c:\python37\lib\site-packages\pandas\core\ops.py in wrapper(self, other)
       1848         filler = (fill_int if is_self_int_dtype and   is_other_int_dtype
       1849                   else fill_bool)
    -> 1850         res_values = na_op(self.values, ovalues)
       1851         unfilled = self._constructor(res_values,
       1852                                      index=self.index,  name=res_name)

    c:\python37\lib\site-packages\pandas\core\ops.py in na_op(x, y)
       1808                                     "with a scalar of type   [{typ}]"
       1809                                     .format(dtype=x.dtype,
    -> 1810                                              typ=type(y).__name__))
       1811 
       1812         return result

1 个答案:

答案 0 :(得分:0)

围绕各个比较,您需要更多的括号:

((df['Location'].str.contains('- Display')) &
 (df['Lancaster'] == '') &
 (df['Dakota'] == 'D') &
 (df['Spitfire'] == 'S') &
 (df['Hurricane'] == 'H'))

否则,&在下一个等号==之前与对象绑定,而不是下一个比较的结果。

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